Math

QuestionFind the percent increase in population from 59,932 in 1990 to 99,470 in 2020. Round to the nearest percent.

Studdy Solution

STEP 1

Assumptions1. The population of the town in1990 was59,932. The population of the town in2020 was99,4703. We are asked to find the percent increase in population from1990 to2020

STEP 2

First, we need to find the increase in population from1990 to2020. We can do this by subtracting the population in1990 from the population in2020.
Increaseinpopulation=Populationin2020Populationin1990Increase\, in\, population = Population\, in\,2020 - Population\, in\,1990

STEP 3

Now, plug in the given values for the population in1990 and2020 to calculate the increase in population.
Increaseinpopulation=99,47059,932Increase\, in\, population =99,470 -59,932

STEP 4

Calculate the increase in population.
Increaseinpopulation=99,47059,932=39,538Increase\, in\, population =99,470 -59,932 =39,538

STEP 5

Now that we have the increase in population, we can find the percent increase. The percent increase is the increase in population divided by the original population (in1990), multiplied by100.
Percentincrease=(IncreaseinpopulationPopulationin1990)×100Percent\, increase = \left(\frac{Increase\, in\, population}{Population\, in\,1990}\right) \times100

STEP 6

Plug in the values for the increase in population and the population in1990 to calculate the percent increase.
Percentincrease=(39,53859,932)×100Percent\, increase = \left(\frac{39,538}{59,932}\right) \times100

STEP 7

Calculate the percent increase.
Percentincrease=(39,53859,932)×10066%Percent\, increase = \left(\frac{39,538}{59,932}\right) \times100 \approx66\%The population increased by approximately66%.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord