QuestionFind the total charge $C$ for a car rental with insurance, given $C = S + I$ where $S = 18.95 + 0.60M$ and $I = 5.80 + 0.15M$ .

Studdy Solution

STEP 1

Assumptions1. The standard charge is given by the function $=18.95+0.60 M$, where $M$ is the number of miles driven. . The insurance charge is given by the function $=5.80+0.15 M$ .
3. The total charge $C$ includes both the standard charge and the insurance charge.

STEP 2

We can express the total charge $C$ as the sum of the standard charge $and the insurance charge$ .
$C = + I$

STEP 3

Now, we can substitute the given functions for $and$ into the equation for $C$ .
$C = (18.95+0.60 M) + (5.80+0.15 M)$

STEP 4

We can simplify this equation by combining like terms. $C =18.95 +.80 +0.60M +0.15M$

STEP 5

Combine the constants and the terms with $M$ .
$C =24.75 +0.75M$ So, the total charge $C$ for a rental that includes insurance is given by the function $C =24.75 +0.75M$ .

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QuestionFind the total charge $C$ for a car rental with insurance, given $C = S + I$ where $S = 18.95 + 0.60M$ and $I = 5.80 + 0.15M$ .

Studdy Solution

STEP 1

Assumptions1. The standard charge is given by the function $=18.95+0.60 M$, where $M$ is the number of miles driven. . The insurance charge is given by the function $=5.80+0.15 M$ .
3. The total charge $C$ includes both the standard charge and the insurance charge.

STEP 2

We can express the total charge $C$ as the sum of the standard charge $and the insurance charge$ .
$C = + I$

STEP 3

Now, we can substitute the given functions for $and$ into the equation for $C$ .
$C = (18.95+0.60 M) + (5.80+0.15 M)$

STEP 4

We can simplify this equation by combining like terms. $C =18.95 +.80 +0.60M +0.15M$

STEP 5

Combine the constants and the terms with $M$ .
$C =24.75 +0.75M$ So, the total charge $C$ for a rental that includes insurance is given by the function $C =24.75 +0.75M$ .

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QuestionFind the total charge CCC for a car rental with insurance, given C=S+IC = S + IC=S+I where S=18.95+0.60MS = 18.95 + 0.60MS=18.95+0.60M and I=5.80+0.15MI = 5.80 + 0.15MI=5.80+0.15M.

Studdy Solution

STEP 1

Assumptions1. The standard charge is given by the function $=18.95+0.60 M$, where $M$ is the number of miles driven. . The insurance charge is given by the function =5.80+0.15M=5.80+0.15 M=5.80+0.15M.3. The total charge CCC includes both the standard charge and the insurance charge.

STEP 2

We can express the total charge CCC as the sum of the standard charge andtheinsurancecharge and the insurance charge andtheinsurancecharge.C=+IC = + IC=+I

STEP 3

Now, we can substitute the given functions for and and and into the equation for CCC.C=(18.95+0.60M)+(5.80+0.15M)C = (18.95+0.60 M) + (5.80+0.15 M)C=(18.95+0.60M)+(5.80+0.15M)

STEP 4

We can simplify this equation by combining like terms.C=18.95+.80+0.60M+0.15MC =18.95 +.80 +0.60M +0.15MC=18.95+.80+0.60M+0.15M

STEP 5

Combine the constants and the terms with MMM.C=24.75+0.75MC =24.75 +0.75MC=24.75+0.75MSo, the total charge CCC for a rental that includes insurance is given by the function C=24.75+0.75MC =24.75 +0.75MC=24.75+0.75M.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionFind the total charge $C$ for a car rental with insurance, given $C = S + I$ where $S = 18.95 + 0.60M$ and $I = 5.80 + 0.15M$ .

Assumptions1. The standard charge is given by the function $=18.95+0.60 M$, where $M$ is the number of miles driven. . The insurance charge is given by the function $=5.80+0.15 M$ .
3. The total charge $C$ includes both the standard charge and the insurance charge.

We can express the total charge $C$ as the sum of the standard charge $and the insurance charge$ .
$C = + I$

Now, we can substitute the given functions for $and$ into the equation for $C$ .
$C = (18.95+0.60 M) + (5.80+0.15 M)$

We can simplify this equation by combining like terms. $C =18.95 +.80 +0.60M +0.15M$

Combine the constants and the terms with $M$ .
$C =24.75 +0.75M$ So, the total charge $C$ for a rental that includes insurance is given by the function $C =24.75 +0.75M$ .