Math

QuestionFind the temperature difference between Juneau and Boston at 6 a.m. and Boston's noon temperature after a 10F10^{\circ} \mathrm{F} rise.

Studdy Solution

STEP 1

Assumptions1. The temperatures provided are accurate and in Fahrenheit. . The temperature in Boston at6 a.m. is -5 degrees Fahrenheit.
3. The temperature in Juneau at6 a.m. is -24 degrees Fahrenheit.
4. The temperature in Boston had risen by10 degrees Fahrenheit by noon.

STEP 2

To find how much lower the temperature in Juneau was than in Boston at6 a.m., we subtract the temperature in Boston from the temperature in Juneau.
Difference=Temperature in JuneauTemperature in Boston\text{Difference} = \text{Temperature in Juneau} - \text{Temperature in Boston}

STEP 3

Now, plug in the given values for the temperatures in Juneau and Boston to calculate the difference.
Difference=24(5)\text{Difference} = -24^{\circ} \mathrm{} - (-5^{\circ} \mathrm{})

STEP 4

Calculate the difference.
Difference=24()=19\text{Difference} = -24^{\circ} \mathrm{} - (-^{\circ} \mathrm{}) = -19^{\circ} \mathrm{}The temperature in Juneau was19 degrees Fahrenheit lower than in Boston at6 a.m.

STEP 5

To find the temperature in Boston at noon, we add the increase in temperature to the temperature at a.m.
Temperature at noon=Temperature at a.m.+Increase in temperature\text{Temperature at noon} = \text{Temperature at a.m.} + \text{Increase in temperature}

STEP 6

Now, plug in the given values for the temperature at6 a.m. and the increase in temperature to calculate the temperature at noon.
Temperature at noon=5+10\text{Temperature at noon} = -5^{\circ} \mathrm{} +10^{\circ} \mathrm{}

STEP 7

Calculate the temperature at noon.
Temperature at noon=5+10=5\text{Temperature at noon} = -5^{\circ} \mathrm{} +10^{\circ} \mathrm{} =5^{\circ} \mathrm{}The temperature in Boston at noon was5 degrees Fahrenheit.

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