Math  /  Data & Statistics

QuestionThe table gives information about the times taken by 80 people to run a race.
Time taken ( tt minutes) Cumulative Frequency 50<t601550<t703150<t805250<t906650<t1007450<t11080\begin{array}{ll} 50<t \leq 60 & 15 \\ 50<t \leq 70 & 31 \\ 50<t \leq 80 & 52 \\ 50<t \leq 90 & 66 \\ 50<t \leq 100 & 74 \\ 50<t \leq 110 & 80 \end{array}
This information is shown on the cumulative frequency graph below.
Use this graph to find an estimate for the interquartile range of the times taken.

Studdy Solution

STEP 1

What is this asking? We need to find the difference between the time it took the person at the 75% mark and the 25% mark to finish the race, using the graph. Watch out! Don't mix up the median and the quartiles!
And be precise when reading values from the graph!

STEP 2

1. Find the Upper Quartile
2. Find the Lower Quartile
3. Calculate the Interquartile Range

STEP 3

The upper quartile represents the time taken by the runner at the **75%** mark.
Since there are **80** runners, we need to find the position of the 75% runner.
We calculate this by multiplying 0.7580=600.75 \cdot 80 = 60.

STEP 4

So, the upper quartile is the time taken by the **60th** runner.
Locate **60** on the vertical *cumulative frequency* axis.
Draw a horizontal line across to the curve, and then a vertical line down to the *time* axis.

STEP 5

The upper quartile appears to be approximately **87** minutes, based on where our vertical line intersects the time axis.

STEP 6

The lower quartile represents the time taken by the runner at the **25%** mark.
We calculate the position of the lower quartile with 0.2580=200.25 \cdot 80 = 20.

STEP 7

So, the lower quartile is the time taken by the **20th** runner.
Locate **20** on the vertical *cumulative frequency* axis.
Draw a horizontal line across to the curve, and then a vertical line down to the *time* axis.

STEP 8

The lower quartile appears to be approximately **67** minutes.

STEP 9

The interquartile range is the difference between the upper and lower quartiles.
So, we subtract the lower quartile time from the upper quartile time: 8767=2087 - 67 = 20.

STEP 10

The interquartile range is approximately **20** minutes.

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