Math  /  Algebra

QuestionThe table below gives values of an invertible function f(x)f(x) : \begin{tabular}{|cccccc|} \hlinexx & -2 & -1 & 0 & 1 & 2 \\ f(x)f(x) & -3 & 4 & 2 & 5 & 0 \\ \hline \end{tabular} (a) f(0)=f(0)= \square (b) f()=0f(\square)=0 (c) f1(0)=f^{-1}(0)= \square (d) f1()=0f^{-1}(\square)=0 \square

Studdy Solution

STEP 1

1. We are given a table of values for an invertible function f(x) f(x) .
2. We need to find specific values and inverses based on the table.

STEP 2

1. Use the table to find the value of f(0) f(0) .
2. Use the table to find the value of x x such that f(x)=0 f(x) = 0 .
3. Determine f1(0) f^{-1}(0) using the table.
4. Determine f1(x) f^{-1}(x) such that f(x)=0 f(x) = 0 .

STEP 3

Look at the table to find f(0) f(0) .
From the table, when x=0 x = 0 , f(x)=2 f(x) = 2 .
Thus, f(0)=2 f(0) = 2 .

STEP 4

Look at the table to find x x such that f(x)=0 f(x) = 0 .
From the table, when x=2 x = 2 , f(x)=0 f(x) = 0 .
Thus, f()=0 f(\square) = 0 where =2 \square = 2 .

STEP 5

Determine f1(0) f^{-1}(0) .
Since f(2)=0 f(2) = 0 , then f1(0)=2 f^{-1}(0) = 2 .

STEP 6

Determine f1(x) f^{-1}(x) such that f(x)=0 f(x) = 0 .
Since f(2)=0 f(2) = 0 , then f1()=0 f^{-1}(\square) = 0 where =2 \square = 2 .
The answers are: (a) f(0)=2 f(0) = 2 (b) f(2)=0 f(2) = 0 (c) f1(0)=2 f^{-1}(0) = 2 (d) f1(2)=0 f^{-1}(2) = 0

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