QuestionCalculate $(5+16) \div 7 - 2$ .

Studdy Solution

STEP 1

Assumptions1. We are given the expression $(5+16) \div7-$ . . We follow the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

STEP 2

First, we need to solve the operation inside the brackets.
$(5+16) \div7-2$

STEP 3

Calculate the sum inside the brackets.
$21 \div7-2$

STEP 4

Next, we perform the division operation.
$21 \div7-2$

STEP 5

Calculate the division operation.
$3-2$

STEP 6

Finally, we perform the subtraction operation.
$3-2$

STEP 7

Calculate the subtraction operation.
$1$ So, the solution to the expression $(5+16) \div7-2$ is1.

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QuestionCalculate $(5+16) \div 7 - 2$ .

Studdy Solution

STEP 1

Assumptions1. We are given the expression $(5+16) \div7-$ . . We follow the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

STEP 2

First, we need to solve the operation inside the brackets.
$(5+16) \div7-2$

STEP 3

Calculate the sum inside the brackets.
$21 \div7-2$

STEP 4

Next, we perform the division operation.
$21 \div7-2$

STEP 5

Calculate the division operation.
$3-2$

STEP 6

Finally, we perform the subtraction operation.
$3-2$

STEP 7

Calculate the subtraction operation.
$1$ So, the solution to the expression $(5+16) \div7-2$ is1.

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QuestionCalculate (5+16)÷7−2(5+16) \div 7 - 2(5+16)÷7−2.

Studdy Solution

STEP 1

Assumptions1. We are given the expression (5+16)÷7−(5+16) \div7-(5+16)÷7−. . We follow the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

STEP 2

First, we need to solve the operation inside the brackets.(5+16)÷7−2(5+16) \div7-2(5+16)÷7−2

STEP 3

Calculate the sum inside the brackets.21÷7−221 \div7-221÷7−2

STEP 4

Next, we perform the division operation.21÷7−221 \div7-221÷7−2

STEP 5

Calculate the division operation.3−23-23−2

STEP 6

Finally, we perform the subtraction operation.3−23-23−2

STEP 7

Calculate the subtraction operation.111So, the solution to the expression (5+16)÷7−2(5+16) \div7-2(5+16)÷7−2 is1.

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QuestionCalculate $(5+16) \div 7 - 2$ .

Assumptions1. We are given the expression $(5+16) \div7-$ . . We follow the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

First, we need to solve the operation inside the brackets.
$(5+16) \div7-2$

Calculate the sum inside the brackets.
$21 \div7-2$

Next, we perform the division operation.
$21 \div7-2$

Calculate the division operation.
$3-2$

Finally, we perform the subtraction operation.
$3-2$

Calculate the subtraction operation.
$1$ So, the solution to the expression $(5+16) \div7-2$ is1.