Math  /  Algebra

QuestionThe seniors on the student council bought a total of 36 plants to use in landscaping the front of the school. They bought some araleas (a) that cost $6\$ 6 each and some lilies (s) that costs $5\$ 5 each. They spent a total of $196\$ 196 on these plants. Which system of equations can be used to determine the amout azaleas and lilies? (A) {a+s=365a+6s=196\left\{\begin{array}{c}a+s=36 \\ 5 a+6 s=196\end{array}\right.
B {a+s=366a+5s=196\left\{\begin{array}{c}a+s=36 \\ 6 a+5 s=196\end{array}\right. C) {a+s=1966a+5s=36\left\{\begin{array}{c}a+s=196 \\ 6 a+5 s=36\end{array}\right. (D) {a+s=1965a+6s=36\left\{\begin{array}{l}a+s=196 \\ 5 a+6 s=36\end{array}\right.

Studdy Solution

STEP 1

1. The total number of plants purchased is 36.
2. Azaleas cost \$6 each, and lilies cost \$5 each.
3. The total amount spent on the plants is \$196.
4. We need to find the correct system of equations that represents this situation.

STEP 2

1. Establish equations based on the total number of plants.
2. Establish equations based on the total cost of the plants.
3. Identify the correct system of equations from the given options.

STEP 3

To represent the total number of plants, we use the equation: a+s=36 a + s = 36 where a a is the number of azaleas and s s is the number of lilies.

STEP 4

To represent the total cost of the plants, we use the equation: 6a+5s=196 6a + 5s = 196 where each azalea costs \$6 and each lily costs \$5.

STEP 5

Compare the established equations with the given options: - Option (A): {a+s=365a+6s=196\left\{\begin{array}{c}a+s=36 \\ 5a+6s=196\end{array}\right. - Option (B): {a+s=366a+5s=196\left\{\begin{array}{c}a+s=36 \\ 6a+5s=196\end{array}\right. - Option (C): {a+s=1966a+5s=36\left\{\begin{array}{c}a+s=196 \\ 6a+5s=36\end{array}\right. - Option (D): {a+s=1965a+6s=36\left\{\begin{array}{l}a+s=196 \\ 5a+6s=36\end{array}\right.
The correct system of equations is: {a+s=366a+5s=196 \boxed{\left\{\begin{array}{c}a+s=36 \\ 6a+5s=196\end{array}\right.}
The correct answer is Option (B).

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