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QuestionA scientist starts at 184 feet below sea level and goes to 257 feet in 2 seconds. Find the rate of change in feet per second.

Studdy Solution

STEP 1

Assumptions1. The submarine starts at184 feet below sea level. After seconds, the submarine is257 feet below sea level3. We need to find the rate of change in the submarine's elevation, in feet per second

STEP 2

First, we need to find the change in the submarine's elevation. We can do this by subtracting the initial elevation from the final elevation.
Change in elevation=Final elevation−Initial elevationChange\, in\, elevation = Final\, elevation - Initial\, elevation

STEP 3

Now, plug in the given values for the initial and final elevations to calculate the change in elevation.
Change in elevation=−257 feet−(−184 feet)Change\, in\, elevation = -257\, feet - (-184\, feet)

STEP 4

Calculate the change in elevation.
Change in elevation=−257 feet−(−184 feet)=−73 feetChange\, in\, elevation = -257\, feet - (-184\, feet) = -73\, feet

STEP 5

Now that we have the change in elevation, we can find the rate of change in the submarine's elevation by dividing the change in elevation by the change in time. The change in time is2 seconds.
Rate of change=Change in elevation/Change in timeRate\, of\, change = Change\, in\, elevation / Change\, in\, time

STEP 6

Plug in the values for the change in elevation and the change in time to calculate the rate of change.
Rate of change=−73 feet/2 secondsRate\, of\, change = -73\, feet /2\, seconds

STEP 7

Calculate the rate of change in the submarine's elevation.
Rate of change=−73 feet/2 seconds=−36.5 feet/secondRate\, of\, change = -73\, feet /2\, seconds = -36.5\, feet/secondThe submarine's elevation is changing at a rate of -36.5 feet per second.

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