Math  /  Algebra

QuestionThe nth n^{\text {th }} term of a sequence is given by 2n+52 n+5 Work out the first three terms of this sequence. a) How much does the sequence go up by between each term? b) Explain how you could have used the nth n^{\text {th }} term rule to answer part a) without working out any of the terms.

Studdy Solution

STEP 1

1. The sequence is defined by the formula for the nth n^{\text{th}} term: an=2n+5 a_n = 2n + 5 .
2. We are tasked with finding the first three terms of the sequence.
3. We need to determine the difference between consecutive terms.
4. We need to explain how the nth n^{\text{th}} term formula can be used to determine the difference without calculating individual terms.

STEP 2

1. Calculate the first three terms of the sequence.
2. Determine the difference between each consecutive term.
3. Explain the use of the nth n^{\text{th}} term formula to find the difference.

STEP 3

Calculate the first term by substituting n=1 n = 1 into the formula:
a1=2(1)+5=2+5=7 a_1 = 2(1) + 5 = 2 + 5 = 7

STEP 4

Calculate the second term by substituting n=2 n = 2 into the formula:
a2=2(2)+5=4+5=9 a_2 = 2(2) + 5 = 4 + 5 = 9

STEP 5

Calculate the third term by substituting n=3 n = 3 into the formula:
a3=2(3)+5=6+5=11 a_3 = 2(3) + 5 = 6 + 5 = 11

STEP 6

Determine the difference between the first and second terms:
a2a1=97=2 a_2 - a_1 = 9 - 7 = 2

STEP 7

Determine the difference between the second and third terms:
a3a2=119=2 a_3 - a_2 = 11 - 9 = 2

STEP 8

Explain how the nth n^{\text{th}} term formula can be used to find the difference:
The nth n^{\text{th}} term formula is an=2n+5 a_n = 2n + 5 . The coefficient of n n (which is 2) represents the constant difference between consecutive terms in an arithmetic sequence. Therefore, without calculating individual terms, we can determine that the sequence increases by 2 between each term.
The first three terms of the sequence are 7, 9, and 11. The sequence increases by 2 between each term. The nth n^{\text{th}} term rule directly indicates this increase.

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