QuestionFind the $x$ -intercept and $y$ -intercept of the line given by $-8x + 10y = -20$ and graph it.

Studdy Solution

STEP 1

Assumptions1. The equation of the line is given by $-8x +10y = -20$ . . The $x$ -intercept is the point where the line crosses the $x$ -axis, at which point $y =0$ .
3. The $y$ -intercept is the point where the line crosses the $y$ -axis, at which point $x =0$ .

STEP 2

First, we find the $x$ -intercept by setting $y =0$ in the equation of the line and solving for $x$ .
$-8x +10(0) = -20$

STEP 3

implify the equation to find the value of $x$ .
$-8x = -20$

STEP 4

olve for $x$ by dividing both sides of the equation by $-8$ .
$x = -20 / -8$

STEP 5

Calculate the value of $x$ .
$x = -20 / -8 =2.5$

STEP 6

Now, we find the $y$ -intercept by setting $x =0$ in the equation of the line and solving for $y$ .
$-8(0) +10y = -20$

STEP 7

implify the equation to find the value of $y$ .
$10y = -20$

STEP 8

olve for $y$ by dividing both sides of the equation by $10$ .
$y = -20 /10$

STEP 9

Calculate the value of $y$ .
$y = -20 / = -2$

STEP 10

The $x$ -intercept is $(2.5,0)$ and the $y$ -intercept is $(0, -2)$ . To graph the line, plot these two points and draw a line through them.
The $x$ -intercept is $2.5$ and the $y$ -intercept is $-2$ .

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QuestionFind the $x$ -intercept and $y$ -intercept of the line given by $-8x + 10y = -20$ and graph it.

Studdy Solution

STEP 1

Assumptions1. The equation of the line is given by $-8x +10y = -20$ . . The $x$ -intercept is the point where the line crosses the $x$ -axis, at which point $y =0$ .
3. The $y$ -intercept is the point where the line crosses the $y$ -axis, at which point $x =0$ .

STEP 2

First, we find the $x$ -intercept by setting $y =0$ in the equation of the line and solving for $x$ .
$-8x +10(0) = -20$

STEP 3

implify the equation to find the value of $x$ .
$-8x = -20$

STEP 4

olve for $x$ by dividing both sides of the equation by $-8$ .
$x = -20 / -8$

STEP 5

Calculate the value of $x$ .
$x = -20 / -8 =2.5$

STEP 6

Now, we find the $y$ -intercept by setting $x =0$ in the equation of the line and solving for $y$ .
$-8(0) +10y = -20$

STEP 7

implify the equation to find the value of $y$ .
$10y = -20$

STEP 8

olve for $y$ by dividing both sides of the equation by $10$ .
$y = -20 /10$

STEP 9

Calculate the value of $y$ .
$y = -20 / = -2$

STEP 10

The $x$ -intercept is $(2.5,0)$ and the $y$ -intercept is $(0, -2)$ . To graph the line, plot these two points and draw a line through them.
The $x$ -intercept is $2.5$ and the $y$ -intercept is $-2$ .

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QuestionFind the xxx-intercept and yyy-intercept of the line given by −8x+10y=−20-8x + 10y = -20−8x+10y=−20 and graph it.

Studdy Solution

STEP 1

Assumptions1. The equation of the line is given by −8x+10y=−20-8x +10y = -20−8x+10y=−20. . The xxx-intercept is the point where the line crosses the xxx-axis, at which point y=0y =0y=0.3. The yyy-intercept is the point where the line crosses the yyy-axis, at which point x=0x =0x=0.

STEP 2

First, we find the xxx-intercept by setting y=0y =0y=0 in the equation of the line and solving for xxx.−8x+10(0)=−20-8x +10(0) = -20−8x+10(0)=−20

STEP 3

implify the equation to find the value of xxx.−8x=−20-8x = -20−8x=−20

STEP 4

olve for xxx by dividing both sides of the equation by −8-8−8.x=−20/−8x = -20 / -8x=−20/−8

STEP 5

Calculate the value of xxx.x=−20/−8=2.5x = -20 / -8 =2.5x=−20/−8=2.5

STEP 6

Now, we find the yyy-intercept by setting x=0x =0x=0 in the equation of the line and solving for yyy.−8(0)+10y=−20-8(0) +10y = -20−8(0)+10y=−20

STEP 7

implify the equation to find the value of yyy.10y=−2010y = -2010y=−20

STEP 8

olve for yyy by dividing both sides of the equation by 101010.y=−20/10y = -20 /10y=−20/10

STEP 9

Calculate the value of yyy.y=−20/=−2y = -20 / = -2y=−20/=−2

STEP 10

The xxx-intercept is (2.5,0)(2.5,0)(2.5,0) and the yyy-intercept is (0,−2)(0, -2)(0,−2). To graph the line, plot these two points and draw a line through them.The xxx-intercept is 2.52.52.5 and the yyy-intercept is −2-2−2.

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QuestionFind the $x$ -intercept and $y$ -intercept of the line given by $-8x + 10y = -20$ and graph it.

Assumptions1. The equation of the line is given by $-8x +10y = -20$ . . The $x$ -intercept is the point where the line crosses the $x$ -axis, at which point $y =0$ .
3. The $y$ -intercept is the point where the line crosses the $y$ -axis, at which point $x =0$ .

First, we find the $x$ -intercept by setting $y =0$ in the equation of the line and solving for $x$ .
$-8x +10(0) = -20$

implify the equation to find the value of $x$ .
$-8x = -20$

olve for $x$ by dividing both sides of the equation by $-8$ .
$x = -20 / -8$

Calculate the value of $x$ .
$x = -20 / -8 =2.5$

Now, we find the $y$ -intercept by setting $x =0$ in the equation of the line and solving for $y$ .
$-8(0) +10y = -20$

implify the equation to find the value of $y$ .
$10y = -20$

olve for $y$ by dividing both sides of the equation by $10$ .
$y = -20 /10$

Calculate the value of $y$ .
$y = -20 / = -2$

The $x$ -intercept is $(2.5,0)$ and the $y$ -intercept is $(0, -2)$ . To graph the line, plot these two points and draw a line through them.
The $x$ -intercept is $2.5$ and the $y$ -intercept is $-2$ .