Math

Question Find dimensions of a rectangle where length is 11yd11 \mathrm{yd} less than 3 times the width, and area is 70yd270 \mathrm{yd}^{2}.

Studdy Solution

STEP 1

Assumptions
1. Let the width of the rectangle be w w yards.
2. The length of the rectangle is 3w11 3w - 11 yards.
3. The area of the rectangle is 70 70 square yards.
4. The area of a rectangle is given by the formula Area=length×width \text{Area} = \text{length} \times \text{width} .

STEP 2

Use the formula for the area of a rectangle to set up an equation with the given information.
Area=length×width \text{Area} = \text{length} \times \text{width}

STEP 3

Substitute the expressions for the length and the area into the area formula.
70=(3w11)×w 70 = (3w - 11) \times w

STEP 4

Distribute w w to both terms inside the parentheses.
70=3w211w 70 = 3w^2 - 11w

STEP 5

Rearrange the equation to form a quadratic equation by moving all terms to one side.
3w211w70=0 3w^2 - 11w - 70 = 0

STEP 6

Factor the quadratic equation, if possible, to find the values of w w .

STEP 7

To factor the quadratic equation, look for two numbers that multiply to 3×(70)=210 3 \times (-70) = -210 and add up to 11 -11 .

STEP 8

The numbers that satisfy these conditions are 21 -21 and 10 10 .

STEP 9

Rewrite the middle term of the quadratic equation using the numbers found in STEP_8.
3w221w+10w70=0 3w^2 - 21w + 10w - 70 = 0

STEP 10

Factor by grouping. Group the first two terms together and the last two terms together.
(3w221w)+(10w70)=0 (3w^2 - 21w) + (10w - 70) = 0

STEP 11

Factor out the greatest common factor from each group.
3w(w7)+10(w7)=0 3w(w - 7) + 10(w - 7) = 0

STEP 12

Factor out (w7) (w - 7) which is common in both terms.
(w7)(3w+10)=0 (w - 7)(3w + 10) = 0

STEP 13

Set each factor equal to zero to solve for w w .
w7=0or3w+10=0 w - 7 = 0 \quad \text{or} \quad 3w + 10 = 0

STEP 14

Solve the first equation for w w .
w=7 w = 7

STEP 15

Solve the second equation for w w .
3w=10 3w = -10
w=103 w = -\frac{10}{3}

STEP 16

Since a width cannot be negative, we discard w=103 w = -\frac{10}{3} and keep w=7 w = 7 yards as the width of the rectangle.

STEP 17

Now that we have the width, we can find the length by using the expression 3w11 3w - 11 .

STEP 18

Substitute w=7 w = 7 into the expression for the length.
length=3(7)11 \text{length} = 3(7) - 11

STEP 19

Calculate the length.
length=2111 \text{length} = 21 - 11

STEP 20

Find the length of the rectangle.
length=10 yards \text{length} = 10 \text{ yards}
The dimensions of the rectangle are a width of 7 yards and a length of 10 yards.

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