Math  /  Algebra

QuestionThe graph of linear function ff passes through the point (1,9)(1,-9) and has a slope of -3 .
What is the zero of ff ?
F 2 G 4 H -6 J -2

Studdy Solution

STEP 1

What is this asking? We're looking for the *x*-value where our line hits the *x*-axis, given a point it goes through and its slope! Watch out! Don't mix up the *x* and *y* values, and make sure you use the slope correctly!

STEP 2

1. Find the equation
2. Find the zero

STEP 3

Alright, let's **start** with the **point-slope form** of a linear equation, which is yy1=m(xx1)y - y_1 = m(x - x_1).
Remember, (x1,y1)(x_1, y_1) is our **given point**, and mm is our **slope**.
This formula is super handy because it tells us how much yy changes based on how much xx changes, all relative to a starting point!

STEP 4

We know our **point** is (1,9)(1, -9), so x1=1x_1 = 1 and y1=9y_1 = -9.
Our **slope**, mm, is 3-3.
Let's **plug** these values into our **point-slope form**: y(9)=3(x1)y - (-9) = -3(x - 1).

STEP 5

Now, let's **simplify**! y+9=3x+3y + 9 = -3x + 3.
See how we distributed the 3-3?
We multiplied it by both xx and 1-1.

STEP 6

Let's **isolate** yy to get our equation in **slope-intercept form** (y=mx+by = mx + b).
We can do this by **subtracting** 99 from both sides of the equation: y=3x+39y = -3x + 3 - 9, which simplifies to y=3x6y = -3x - 6.
Awesome!

STEP 7

The "**zero**" of a function is just a fancy way of saying where the graph crosses the *x*-axis.
This happens when y=0y = 0.
So, let's **substitute** 00 for yy in our equation: 0=3x60 = -3x - 6.

STEP 8

Now, we want to **solve for** xx.
Let's **add** 66 to both sides of the equation to **isolate** the term with xx: 0+6=3x6+60 + 6 = -3x - 6 + 6, which simplifies to 6=3x6 = -3x.

STEP 9

Finally, let's **divide** both sides by 3-3 to get xx all by itself: 63=3x3\frac{6}{-3} = \frac{-3x}{-3}.
This gives us x=2x = -2.
Boom! We found our zero!

STEP 10

The zero of ff is 2-2, which corresponds to answer choice J.

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