QuestionFind the values of the function $f(x)=\sqrt[3]{x}+1$ at $f(-64)$ and $f(27)$ .

Studdy Solution

STEP 1

Assumptions1. The function is defined as $f(x)=\sqrt[3]{x}+1$ . We are asked to find the values of $f(-64)$ and $f(27)$

STEP 2

First, let's find the value of $f(-64)$ . We can do this by substituting $-64$ into the function.
$f(-64)=\sqrt[]{-64}+1$

STEP 3

Now, calculate the cube root of $-64$ .
$\sqrt[3]{-64} = -$

STEP 4

Substitute $-4$ back into the function to find $f(-64)$ .
$f(-64) = -4 +1$

STEP 5

Calculate the value of $f(-64)$ .
$f(-64) = -4 +1 = -3$

STEP 6

Next, let's find the value of $f(27)$ . We can do this by substituting $27$ into the function.
$f(27)=\sqrt[3]{27}+1$

STEP 7

Now, calculate the cube root of $27$ .
$\sqrt[3]{27} =3$

STEP 8

Substitute $3$ back into the function to find $f(27)$ .
$f(27) =3 +1$

STEP 9

Calculate the value of $f(27)$ .
$f(27) =3 + =4$ So, $f(-64) = -3$ and $f(27) =4$ .

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