Math  /  Data & Statistics

QuestionThe frequency table shows the temperatures at noon for 7 days (in C{ }^{\circ} \mathrm{C} ) \begin{tabular}{|c|l|c|} \hline Temperature & Tally marks & Frequency \\ \hline 21 & II & 1 \\ \hline 22 & & 0 \\ \hline 23 & \| & 2 \\ \hline 24 & \|\| & 3 \\ \hline 25 & II & 1 \\ \hline & & Total =7=7 \\ \hline \end{tabular}
Match the statistical value with the term (2 points)
Mean:

Studdy Solution

STEP 1

1. The temperatures are given in a frequency table format.
2. The mean is calculated as the sum of all data points divided by the total number of data points.

STEP 2

1. Calculate the sum of all temperatures.
2. Divide the sum by the total number of days to find the mean.

STEP 3

List the temperatures and their frequencies:
- Temperature 21C21^{\circ} \mathrm{C} occurs 1 time. - Temperature 22C22^{\circ} \mathrm{C} occurs 0 times. - Temperature 23C23^{\circ} \mathrm{C} occurs 2 times. - Temperature 24C24^{\circ} \mathrm{C} occurs 3 times. - Temperature 25C25^{\circ} \mathrm{C} occurs 1 time.

STEP 4

Calculate the sum of all temperatures:
(21×1)+(22×0)+(23×2)+(24×3)+(25×1)=21+0+46+72+25=164(21 \times 1) + (22 \times 0) + (23 \times 2) + (24 \times 3) + (25 \times 1) = 21 + 0 + 46 + 72 + 25 = 164

STEP 5

Divide the sum by the total number of days to find the mean:
Mean=164723.43\text{Mean} = \frac{164}{7} \approx 23.43
The mean temperature is approximately:
23.43C \boxed{23.43^{\circ} \mathrm{C}}

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