Math  /  Algebra

QuestionThe first term of a geometric sequence is 23\frac{2}{3}. The next three terms are 12,38\frac{1}{2}, \frac{3}{8}, and 932\frac{9}{32}. What is the tenth term of the sequence?

Studdy Solution

STEP 1

1. The sequence is geometric, meaning each term is obtained by multiplying the previous term by a constant ratio.
2. The first term of the sequence is 23\frac{2}{3}.
3. The next three terms are 12,38,932\frac{1}{2}, \frac{3}{8}, \frac{9}{32}.
4. We need to find the tenth term of the sequence.

STEP 2

1. Identify the common ratio of the geometric sequence.
2. Use the formula for the nn-th term of a geometric sequence.
3. Calculate the tenth term using the identified common ratio and the formula.

STEP 3

Identify the common ratio of the geometric sequence.
To find the common ratio r r , divide the second term by the first term:
r=1223=12×32=34 r = \frac{\frac{1}{2}}{\frac{2}{3}} = \frac{1}{2} \times \frac{3}{2} = \frac{3}{4}
Verify with the third term:
r=3812=38×21=34 r = \frac{\frac{3}{8}}{\frac{1}{2}} = \frac{3}{8} \times \frac{2}{1} = \frac{3}{4}
And the fourth term:
r=93238=932×83=34 r = \frac{\frac{9}{32}}{\frac{3}{8}} = \frac{9}{32} \times \frac{8}{3} = \frac{3}{4}
The common ratio is 34\frac{3}{4}.

STEP 4

Use the formula for the nn-th term of a geometric sequence.
The formula for the nn-th term an a_n of a geometric sequence is:
an=a1rn1 a_n = a_1 \cdot r^{n-1}
where a1 a_1 is the first term and r r is the common ratio.

STEP 5

Calculate the tenth term using the identified common ratio and the formula.
Substitute the known values into the formula:
a10=23(34)101 a_{10} = \frac{2}{3} \cdot \left(\frac{3}{4}\right)^{10-1}
a10=23(34)9 a_{10} = \frac{2}{3} \cdot \left(\frac{3}{4}\right)^9
Calculate (34)9\left(\frac{3}{4}\right)^9:
(34)9=3949=19683262144 \left(\frac{3}{4}\right)^9 = \frac{3^9}{4^9} = \frac{19683}{262144}
Now calculate a10 a_{10} :
a10=2319683262144=2×196833×262144 a_{10} = \frac{2}{3} \cdot \frac{19683}{262144} = \frac{2 \times 19683}{3 \times 262144}
a10=39366786432 a_{10} = \frac{39366}{786432}
Simplify the fraction:
a10=39366786432=120 a_{10} = \frac{39366}{786432} = \frac{1}{20}
The tenth term of the sequence is:
120 \boxed{\frac{1}{20}}

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