Math

QuestionFind the explicit formula for the arithmetic sequence starting with a1=54a_{1}=54 and the first six terms: 54,73,92,111,130,14954, 73, 92, 111, 130, 149.

Studdy Solution

STEP 1

Assumptions1. The sequence is an arithmetic sequence. The first term of the sequence, a1a_{1}, is543. The sequence is increasing

STEP 2

In an arithmetic sequence, the difference between any two successive terms is constant. This constant difference is called the common difference, denoted by dd. We can find dd by subtracting the first term from the second term.
d=a2a1d = a_{2} - a_{1}

STEP 3

Now, plug in the given values for a1a_{1} and a2a_{2} to calculate the common difference.
d=7354d =73 -54

STEP 4

Calculate the common difference.
d=7354=19d =73 -54 =19

STEP 5

The explicit formula for an arithmetic sequence is given byan=a1+(n1)da_{n} = a_{1} + (n -1) \cdot dwhere- ana_{n} is the nth term of the sequence- a1a_{1} is the first term of the sequence- dd is the common difference- nn is the term number

STEP 6

Now, plug in the given values for a1a_{1} and dd into the formula.
an=54+(n1)19a_{n} =54 + (n -1) \cdot19So, the explicit formula for this sequence is an=54+(n1)19a_{n} =54 + (n -1) \cdot19.

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