Math

Question Find the solution to the equation ln(x1)=1+ln(3x+2)\ln (x-1)=1+\ln (3x+2).

Studdy Solution

STEP 1

Assumptions
1. The equation to solve is ln(x1)=1+ln(3x+2)\ln (x-1) = 1 + \ln (3x+2).
2. We assume that xx is in the domain of both logarithmic functions, meaning x>1x>1 and 3x+2>03x+2>0.
3. We will use properties of logarithms to solve the equation.

STEP 2

First, we need to simplify the equation using logarithmic properties. We can combine the logarithms on the right-hand side using the property lna+lnb=ln(ab)\ln a + \ln b = \ln(ab).
ln(x1)=ln(e)+ln(3x+2)\ln (x-1) = \ln(e) + \ln (3x+2)

STEP 3

Since ln(e)=1\ln(e) = 1, we can rewrite the equation as:
ln(x1)=ln(e(3x+2))\ln (x-1) = \ln(e \cdot (3x+2))

STEP 4

Now, apply the property lna=lnba=b\ln a = \ln b \Rightarrow a = b to equate the arguments of the logarithms.
(x1)=e(3x+2)(x-1) = e \cdot (3x+2)

STEP 5

Distribute ee on the right-hand side of the equation.
(x1)=3ex+2e(x-1) = 3ex + 2e

STEP 6

Now, we need to isolate xx. First, move all terms involving xx to one side and constants to the other side.
x3ex=2e+1x - 3ex = 2e + 1

STEP 7

Factor out xx on the left-hand side.
x(13e)=2e+1x(1 - 3e) = 2e + 1

STEP 8

Divide both sides by (13e)(1 - 3e) to solve for xx.
x=2e+113ex = \frac{2e + 1}{1 - 3e}

STEP 9

We need to simplify the right-hand side. Since there is no simple form for this expression, we can check the given options to see if any of them match the simplified form of xx.

STEP 10

We can see that none of the given options directly match the form of xx we have derived. Therefore, we can conclude that the correct answer is "none".
The most correct answer for the solutions of the equation ln(x1)=1+ln(3x+2)\ln (x-1) = 1 + \ln (3x+2) is "none".

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord