Math

QuestionConvert the distance between two oxygen atom centers, 1.21×108cm1.21 \times 10^{-8} \mathrm{cm}, to nm\mathrm{nm}.

Studdy Solution

STEP 1

Assumptions1. The distance between the centers of two oxygen atoms in an oxygen molecule is 1.21×1081.21 \times10^{-8} cm. . We need to convert this distance from cm to nm.
3. The conversion factor between cm and nm is1 cm = 10710^7 nm.

STEP 2

We start by writing down the conversion factor between cm and nm.
1cm=107nm1\, cm =10^7\, nm

STEP 3

Next, we express the given distance in cm as a product of the distance and the conversion factor.
Distanceinnm=Distanceincm×ConversionfactorDistance\, in\, nm = Distance\, in\, cm \times Conversion\, factor

STEP 4

Now, plug in the given values for the distance in cm and the conversion factor to calculate the distance in nm.
Distanceinnm=1.21×108cm×107nm/cmDistance\, in\, nm =1.21 \times10^{-8}\, cm \times10^7\, nm/cm

STEP 5

Perform the multiplication to find the distance in nm.
Distanceinnm=1.21×108×107=1.21nmDistance\, in\, nm =1.21 \times10^{-8} \times10^7 =1.21 \, nmThe distance between the centers of two oxygen atoms in an oxygen molecule is1.21 nm.

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