Math

QuestionFind the weekly profit function P(x)P(x) for T-shirts with demand q=50x+7200q=-50x+7200 and cost C(x)=1800x+340200C(x)=-1800x+340200. Also, find the break-even price.

Studdy Solution

STEP 1

Assumptions1. The demand equation is given by q=50x+7200q=-50x+7200 where qq is the number of shirts sold in a week and xx is the price per shirt. . The cost function is given by C(x)=1800x+340200C(x)=-1800x+340200 where C(x)C(x) is the weekly cost and xx is the price per shirt.
3. The profit function is given by (x)=R(x)C(x)(x)=R(x)-C(x) where R(x)R(x) is the revenue, C(x)C(x) is the cost and xx is the price per shirt.
4. We are not given a revenue function, but we know that revenue is the product of the price per shirt and the number of shirts sold, i.e., R(x)=xqR(x)=xq.

STEP 2

First, we need to find the revenue function R(x)R(x). We can do this by multiplying the price per shirt xx with the demand equation qq.
R(x)=xqR(x) = xq

STEP 3

Now, plug in the given demand equation for qq to calculate the revenue function.
R(x)=x(50x+7200)R(x) = x(-50x+7200)

STEP 4

implify the revenue function.
R(x)=50x2+7200xR(x) = -50x^2+7200x

STEP 5

Now that we have the revenue function, we can find the profit function (x)(x) by subtracting the cost function C(x)C(x) from the revenue function R(x)R(x).
(x)=R(x)C(x)(x) = R(x) - C(x)

STEP 6

Plug in the values for the revenue function and the cost function to calculate the profit function.
(x)=(50x2+7200x)(1800x+340200)(x) = (-50x^2+7200x) - (-1800x+340200)

STEP 7

implify the profit function.
(x)=50x2+7200x+1800x340200(x) = -50x^2+7200x+1800x-340200

STEP 8

Combine like terms in the profit function.
(x)=50x2+9000x340200(x) = -50x^2+9000x-340200This is the weekly profit as a function of the price per shirt xx.

STEP 9

To break even, the profit must be zero. So, we set the profit function equal to zero and solve for xx.
50x2+900x340200=-50x^2+900x-340200 =

STEP 10

This is a quadratic equation in the form ax2+bx+c=0ax^2+bx+c=0. We can solve it using the quadratic formula x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

STEP 11

Plug in the values for aa, bb, and cc into the quadratic formula to solve for xx.
x=9000±90004(50)(340200)(50)x=\frac{-9000\pm\sqrt{9000^-4(-50)(-340200)}}{(-50)}

STEP 12

implify the expression under the square root.
x=9000±8100000068040000100x=\frac{-9000\pm\sqrt{81000000-68040000}}{-100}

STEP 13

Calculate the value under the square root.
x=9000±12960000100x=\frac{-9000\pm\sqrt{12960000}}{-100}

STEP 14

Take the square root.
x=9000±3600100x=\frac{-9000\pm3600}{-100}

STEP 15

olve for xx.
x=9000+3600100 or x=90003600100x=\frac{-9000+3600}{-100} \text{ or } x=\frac{-9000-3600}{-100}

STEP 16

Calculate the values for xx.
x=54 or x=126x=54 \text{ or } x=126So, you break even when you charge either 54or54 or 126 per shirt. When you set the price per shirt to one of these values, your profit is $0.

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