Math  /  Numbers & Operations

Question13=7293=13313=2163=\begin{array}{l}\sqrt[3]{1}= \\ \sqrt[3]{729}= \\ \sqrt[3]{1331}= \\ \sqrt[3]{216}=\end{array}

Studdy Solution

STEP 1

1. We are given a set of cube root expressions to evaluate.
2. We need to find the cube root of each number provided.

STEP 2

1. Evaluate 13\sqrt[3]{1}.
2. Evaluate 7293\sqrt[3]{729}.
3. Evaluate 13313\sqrt[3]{1331}.
4. Evaluate 2163\sqrt[3]{216}.

STEP 3

Evaluate 13\sqrt[3]{1}.
The cube root of 11 is the number that, when multiplied by itself three times, equals 11.
13=1\sqrt[3]{1} = 1

STEP 4

Evaluate 7293\sqrt[3]{729}.
The cube root of 729729 is the number that, when multiplied by itself three times, equals 729729.
Since 9×9×9=7299 \times 9 \times 9 = 729, we have:
7293=9\sqrt[3]{729} = 9

STEP 5

Evaluate 13313\sqrt[3]{1331}.
The cube root of 13311331 is the number that, when multiplied by itself three times, equals 13311331.
Since 11×11×11=133111 \times 11 \times 11 = 1331, we have:
13313=11\sqrt[3]{1331} = 11

STEP 6

Evaluate 2163\sqrt[3]{216}.
The cube root of 216216 is the number that, when multiplied by itself three times, equals 216216.
Since 6×6×6=2166 \times 6 \times 6 = 216, we have:
2163=6\sqrt[3]{216} = 6
The solutions to the cube root expressions are:
13=17293=913313=112163=6\begin{array}{l} \sqrt[3]{1} = 1 \\ \sqrt[3]{729} = 9 \\ \sqrt[3]{1331} = 11 \\ \sqrt[3]{216} = 6 \\ \end{array}

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