QuestionWhat is the name of the compound $\mathrm{Cu}_{2} \mathrm{SO}_{4}$ ?

Studdy Solution

STEP 1

Assumptions1. The compound is $\mathrm{Cu}_{} \mathrm{}_{4}$ . The compound is a binaryionic compound, which consists of a metal (copper, Cu) and a polyatomic ion (sulfate, SO4).
3. The compound follows the naming convention ofionic compounds, which is name of the cation (metal) + name of the anion (non-metal or polyatomic ion).
4. The metal in the compound can have more than one possible charge, so we need to specify the charge in the name.

STEP 2

First, we need to identify the cation (metal) in the compound. In this case, it's copper (Cu).

STEP 3

Next, we need to identify the anion (polyatomic ion) in the compound. In this case, it's sulfate ().

STEP 4

Now, we need to determine the charge of the copper (Cu). The sulfate ion (4) has a charge of -2. Since the compound is neutral overall, the total charge of the two copper ions must be +2. Therefore, each copper ion has a charge of +1.

STEP 5

We can now name the compound. The name of the compound is name of the cation (metal) + (charge of the cation in Roman numerals in parentheses) + name of the anion (non-metal or polyatomic ion).

STEP 6

Plug in the values for the cation, its charge, and the anion to get the name of the compound.
$Name\, of\, compound = Copper\, ()\,ulfate$ The correct name for the compound $\mathrm{Cu}_{2} \mathrm{}_{4}$ is Copper ()ulfate.

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QuestionWhat is the name of the compound $\mathrm{Cu}_{2} \mathrm{SO}_{4}$ ?

Studdy Solution

STEP 1

STEP 2

First, we need to identify the cation (metal) in the compound. In this case, it's copper (Cu).

STEP 3

Next, we need to identify the anion (polyatomic ion) in the compound. In this case, it's sulfate ().

STEP 4

Now, we need to determine the charge of the copper (Cu). The sulfate ion (4) has a charge of -2. Since the compound is neutral overall, the total charge of the two copper ions must be +2. Therefore, each copper ion has a charge of +1.

STEP 5

We can now name the compound. The name of the compound is name of the cation (metal) + (charge of the cation in Roman numerals in parentheses) + name of the anion (non-metal or polyatomic ion).

STEP 6

Plug in the values for the cation, its charge, and the anion to get the name of the compound.
$Name\, of\, compound = Copper\, ()\,ulfate$ The correct name for the compound $\mathrm{Cu}_{2} \mathrm{}_{4}$ is Copper ()ulfate.

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QuestionWhat is the name of the compound Cu2SO4\mathrm{Cu}_{2} \mathrm{SO}_{4}Cu2​SO4​?

Studdy Solution

STEP 1

STEP 2

First, we need to identify the cation (metal) in the compound. In this case, it's copper (Cu).

STEP 3

Next, we need to identify the anion (polyatomic ion) in the compound. In this case, it's sulfate ().

STEP 4

Now, we need to determine the charge of the copper (Cu). The sulfate ion (4) has a charge of -2. Since the compound is neutral overall, the total charge of the two copper ions must be +2. Therefore, each copper ion has a charge of +1.

STEP 5

We can now name the compound. The name of the compound is name of the cation (metal) + (charge of the cation in Roman numerals in parentheses) + name of the anion (non-metal or polyatomic ion).

STEP 6

Plug in the values for the cation, its charge, and the anion to get the name of the compound.Name of compound=Copper () ulfateName\, of\, compound = Copper\, ()\,ulfateNameofcompound=Copper()ulfateThe correct name for the compound Cu24\mathrm{Cu}_{2} \mathrm{}_{4}Cu2​4​ is Copper ()ulfate.

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QuestionWhat is the name of the compound $\mathrm{Cu}_{2} \mathrm{SO}_{4}$ ?

Plug in the values for the cation, its charge, and the anion to get the name of the compound.
$Name\, of\, compound = Copper\, ()\,ulfate$ The correct name for the compound $\mathrm{Cu}_{2} \mathrm{}_{4}$ is Copper ()ulfate.