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QuestionPerform the following calculations with correct significant digits:
1. 2.800 g−1.47 g=□g2.800 \mathrm{~g}-1.47 \mathrm{~g}=\square \mathrm{g}
2. 1.700 g−0.57 g=□g1.700 \mathrm{~g}-0.57 \mathrm{~g}=\square \mathrm{g}
3. 14.700 g+1.3 g=□g14.700 \mathrm{~g}+1.3 \mathrm{~g}=\square \mathrm{g}

Studdy Solution

STEP 1

Assumptions1. We are dealing with addition and subtraction of measurements in grams. . The number of significant digits in the result should match the least number of significant digits in the given measurements.

STEP 2

First, let's perform the subtraction for the first measurement.
2.800 g−1.47 g=□ g2.800 \, g -1.47 \, g = \square \, g

STEP 3

Subtract the values.
2.800 g−1.47 g=1.33 g2.800 \, g -1.47 \, g =1.33 \, g

STEP 4

The least number of significant digits in the given measurements is3 (in1.47 g). Therefore, the result should also have3 significant digits. So, the result for the first measurement is1.33 g.

STEP 5

Next, let's perform the subtraction for the second measurement.
1.700 g−0.57 g=□ g1.700 \, g -0.57 \, g = \square \, g

STEP 6

Subtract the values.
1.700 g−0.57 g=1.13 g1.700 \, g -0.57 \, g =1.13 \, g

STEP 7

The least number of significant digits in the given measurements is3 (in0.57 g). Therefore, the result should also have3 significant digits. So, the result for the second measurement is1.13 g.

STEP 8

Finally, let's perform the addition for the third measurement.
14.700 g+1.3 g=□ g14.700 \, g +1.3 \, g = \square \, g

STEP 9

Add the values.
14.700 g+.3 g=16. g14.700 \, g +.3 \, g =16. \, g

STEP 10

The least number of significant digits in the given measurements is2 (in.3 g). Therefore, the result should also have2 significant digits. So, the result for the third measurement is16.0 g.
So, the solutions are.2.800 g -.47 g =.33 g2..700 g -0.57 g =.13 g3.14.700 g +.3 g =16.0 g

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