Math Snap

STEP 1

Assumptions1. The given mathematical expression is $\frac{b^{}- c^{}}{a+c-b}$
. The values to be substituted are b = and c =4

STEP 2

First, we substitute the given values of b and c into the expression.$$\frac{b^{2}-2 c^{2}}{a+c-b} = \frac{(2)^{2}-2 (4)^{2}}{a+4-2}$$

STEP 3

Next, we simplify the numerator of the expression by calculating the square of b and c, and then subtracting the two.
$$\frac{(2)^{2}-2 ()^{2}}{a+-2} = \frac{-2(16)}{a+-2}$$

STEP 4

Continue simplifying the numerator.
$$\frac{4-2(16)}{a+4-2} = \frac{4-32}{a+4-2}$$

STEP 5

Calculate the final value of the numerator.
$$\frac{4-32}{a+4-2} = \frac{-28}{a+4-2}$$

STEP 6

Now, simplify the denominator of the expression.
$$\frac{-28}{a+4-2} = \frac{-28}{a+2}$$

So, the expression in terms of 'a' after substituting the values b =2 and c =4 is$$\frac{-28}{a+2}$$