Math

Question Solve the linear equation 3y+2215y=03y + 22 - 15y = 0 for the value of yy.

Studdy Solution

STEP 1

Assumptions
1. The given equation is 3y+2215y=03y + 22 - 15y = 0.
2. We need to solve for the variable yy.

STEP 2

Combine like terms on the left side of the equation. Like terms are terms that contain the same variable raised to the same power.
3y15y+22=03y - 15y + 22 = 0

STEP 3

Subtract 15y15y from 3y3y to simplify the equation.
12y+22=0-12y + 22 = 0

STEP 4

Subtract 2222 from both sides of the equation to isolate the term with the variable yy on one side.
12y=22-12y = -22

STEP 5

Divide both sides of the equation by 12-12 to solve for yy.
y=2212y = \frac{-22}{-12}

STEP 6

Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 22.
y=22/212/2y = \frac{-22 / 2}{-12 / 2}

STEP 7

Complete the simplification to find the value of yy.
y=116y = \frac{11}{6}
The solution to the equation 3y+2215y=03y + 22 - 15y = 0 is y=116y = \frac{11}{6}.

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