Math  /  Algebra

QuestionSolve the following exponential equation. Express the solution set in terms of natural logarithms or common los e5x27=25150e^{5 x-2}-7=25150

Studdy Solution

STEP 1

1. The equation e5x27=25150 e^{5x-2} - 7 = 25150 is an exponential equation.
2. We will use natural logarithms to solve for x x .

STEP 2

1. Isolate the exponential term e5x2 e^{5x-2} .
2. Apply the natural logarithm to both sides.
3. Solve for x x .

STEP 3

Add 7 to both sides of the equation to isolate the exponential term:
e5x27=25150 e^{5x-2} - 7 = 25150 e5x2=25150+7 e^{5x-2} = 25150 + 7 e5x2=25157 e^{5x-2} = 25157

STEP 4

Apply the natural logarithm to both sides of the equation to remove the exponential:
ln(e5x2)=ln(25157) \ln(e^{5x-2}) = \ln(25157)
Using the property of logarithms, ln(ey)=y\ln(e^y) = y, we simplify the left side:
5x2=ln(25157) 5x - 2 = \ln(25157)

STEP 5

Solve for x x by first adding 2 to both sides:
5x2=ln(25157) 5x - 2 = \ln(25157) 5x=ln(25157)+2 5x = \ln(25157) + 2
Then divide both sides by 5:
x=ln(25157)+25 x = \frac{\ln(25157) + 2}{5}
The solution set in terms of natural logarithms is:
x=ln(25157)+25 x = \frac{\ln(25157) + 2}{5}

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