Math  /  Algebra

Question(x+5)216=0(x+5)^{2}-16=0

Studdy Solution

STEP 1

1. The equation (x+5)216=0(x+5)^2 - 16 = 0 is a quadratic equation in disguise.
2. Solving the equation will involve isolating the squared term and then taking the square root.

STEP 2

1. Isolate the squared term.
2. Take the square root of both sides.
3. Solve for x x .

STEP 3

Start by isolating the squared term (x+5)2(x+5)^2 on one side of the equation. Add 16 to both sides:
(x+5)216+16=0+16(x+5)^2 - 16 + 16 = 0 + 16 (x+5)2=16(x+5)^2 = 16

STEP 4

Take the square root of both sides to solve for x+5 x+5 . Remember that taking the square root introduces both a positive and a negative solution:
(x+5)2=±16\sqrt{(x+5)^2} = \pm \sqrt{16} x+5=±4x+5 = \pm 4

STEP 5

Solve for x x by considering both the positive and negative solutions:
For the positive solution: x+5=4x+5 = 4 Subtract 5 from both sides: x=45x = 4 - 5 x=1x = -1
For the negative solution: x+5=4x+5 = -4 Subtract 5 from both sides: x=45x = -4 - 5 x=9x = -9
The solutions for x x are:
x=1andx=9 x = -1 \quad \text{and} \quad x = -9

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