Math

QuestionSolve the equation ex+7=5e^{x+7}=5 and express the solution using natural logarithms.

Studdy Solution

STEP 1

Assumptions1. The base of the natural logarithm is e (uler's number, approximately.71828) . The equation is in the form ex+7=5e^{x+7}=5
3. We need to solve for x

STEP 2

To solve for x in the given equation, we need to isolate x. We can do this by taking the natural logarithm on both sides of the equation. The natural logarithm of a number is the exponent to which the base e must be raised to produce that number.ln(ex+7)=ln(5)\ln(e^{x+7})=\ln(5)

STEP 3

The property of logarithms states that ln(ab)=bln(a)\ln(a^b)=b\ln(a). Therefore, we can simplify the left side of the equation.
ln(ex+7)=(x+7)ln(e)\ln(e^{x+7})=(x+7)\ln(e)

STEP 4

Since the natural logarithm of e is1 (ln(e)=1\ln(e)=1), the left side of the equation simplifies to(x+7)ln(e)=x+7(x+7)\ln(e) = x+7

STEP 5

Now, we have the equationx+7=ln(5)x+7=\ln(5)

STEP 6

To solve for x, we need to subtract from both sides of the equation.
x=ln(5)x=\ln(5)-

STEP 7

This is the solution for x in terms of natural logarithms.
The solution to the equation ex+7=5e^{x+7}=5 isx=ln(5)7x=\ln(5)-7

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