Math / Algebra

QuestionSolve the equation and check. $x=\square$

Studdy Solution

STEP 1

1. The equation given is linear, $5(x - 2) = 29$ .
2. To solve for $x$ , we'll isolate $x$ by performing algebraic operations.
3. After solving for $x$ , we will check the solution by substituting it back into the original equation to verify correctness.

STEP 2

1. Distribute the multiplication on the left-hand side of the equation.
2. Isolate the term with $x$ by performing algebraic operations.
3. Solve for $x$ .
4. Check the solution by substituting it back into the original equation.

STEP 3

Distribute the 5 on the left-hand side of the equation.
$5(x - 2) = 29$ $5x - 10 = 29$

STEP 4

Isolate the term with $x$ by adding 10 to both sides of the equation.
$5x - 10 + 10 = 29 + 10$ $5x = 39$

STEP 5

Solve for $x$ by dividing both sides by 5.
$x = \frac{39}{5}$ $x = 7.8$

STEP 6

Check the solution by substituting $x = 7.8$ back into the original equation.
$5(7.8 - 2) = 29$ $5(5.8) = 29$ $29 = 29$
Since the left-hand side equals the right-hand side, the solution is verified.
Solution: $x = 7.8$

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QuestionSolve the equation and check. $x=\square$

Studdy Solution

STEP 1

1. The equation given is linear, $5(x - 2) = 29$ .
2. To solve for $x$ , we'll isolate $x$ by performing algebraic operations.
3. After solving for $x$ , we will check the solution by substituting it back into the original equation to verify correctness.

STEP 2

1. Distribute the multiplication on the left-hand side of the equation.
2. Isolate the term with $x$ by performing algebraic operations.
3. Solve for $x$ .
4. Check the solution by substituting it back into the original equation.

STEP 3

Distribute the 5 on the left-hand side of the equation.
$5(x - 2) = 29$ $5x - 10 = 29$

STEP 4

Isolate the term with $x$ by adding 10 to both sides of the equation.
$5x - 10 + 10 = 29 + 10$ $5x = 39$

STEP 5

Solve for $x$ by dividing both sides by 5.
$x = \frac{39}{5}$ $x = 7.8$

STEP 6

Check the solution by substituting $x = 7.8$ back into the original equation.
$5(7.8 - 2) = 29$ $5(5.8) = 29$ $29 = 29$
Since the left-hand side equals the right-hand side, the solution is verified.
Solution: $x = 7.8$

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QuestionSolve the equation and check. x=□x=\squarex=□

Studdy Solution

STEP 1

1. The equation given is linear, 5(x−2)=295(x - 2) = 295(x−2)=29.2. To solve for xxx, we'll isolate xxx by performing algebraic operations.3. After solving for xxx, we will check the solution by substituting it back into the original equation to verify correctness.

STEP 2

1. Distribute the multiplication on the left-hand side of the equation.2. Isolate the term with xxx by performing algebraic operations.3. Solve for xxx.4. Check the solution by substituting it back into the original equation.

STEP 3

Distribute the 5 on the left-hand side of the equation.5(x−2)=29 5(x - 2) = 29 5(x−2)=29 5x−10=29 5x - 10 = 29 5x−10=29

STEP 4

Isolate the term with xxx by adding 10 to both sides of the equation.5x−10+10=29+10 5x - 10 + 10 = 29 + 10 5x−10+10=29+10 5x=39 5x = 39 5x=39

STEP 5

Solve for xxx by dividing both sides by 5.x=395 x = \frac{39}{5} x=539​ x=7.8 x = 7.8 x=7.8

STEP 6

Check the solution by substituting x=7.8x = 7.8x=7.8 back into the original equation.5(7.8−2)=29 5(7.8 - 2) = 29 5(7.8−2)=29 5(5.8)=29 5(5.8) = 29 5(5.8)=29 29=29 29 = 29 29=29Since the left-hand side equals the right-hand side, the solution is verified.Solution: x=7.8 x = 7.8 x=7.8

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QuestionSolve the equation and check. $x=\square$

1. The equation given is linear, $5(x - 2) = 29$ .
2. To solve for $x$ , we'll isolate $x$ by performing algebraic operations.
3. After solving for $x$ , we will check the solution by substituting it back into the original equation to verify correctness.

1. Distribute the multiplication on the left-hand side of the equation.
2. Isolate the term with $x$ by performing algebraic operations.
3. Solve for $x$ .
4. Check the solution by substituting it back into the original equation.

Distribute the 5 on the left-hand side of the equation.
$5(x - 2) = 29$ $5x - 10 = 29$

Isolate the term with $x$ by adding 10 to both sides of the equation.
$5x - 10 + 10 = 29 + 10$ $5x = 39$

Solve for $x$ by dividing both sides by 5.
$x = \frac{39}{5}$ $x = 7.8$

Check the solution by substituting $x = 7.8$ back into the original equation.
$5(7.8 - 2) = 29$ $5(5.8) = 29$ $29 = 29$
Since the left-hand side equals the right-hand side, the solution is verified.
Solution: $x = 7.8$