Math

QuestionSolve the equation 7(3x5)=3(x+2)197(3x-5)=3(x+2)-19 and express the answer as an integer, simplified fraction, or decimal (2 decimal places).

Studdy Solution

STEP 1

Assumptions1. The equation is linear and in the form of ax+b=cx+dax + b = cx + d . We are solving for the variable xx
3. The solution should be expressed as an integer, a simplified fraction, or a decimal rounded to two decimal places

STEP 2

First, we need to distribute the numbers outside the parentheses on both sides of the equation.
7(x5)=21x357(x -5) =21x -35(x+2)=x+6(x +2) =x +6So, the equation becomes21x35=x+621x -35 =x +6

STEP 3

Next, we need to isolate xx by moving all terms with xx to one side of the equation and constants to the other side.Subtract 3x3x from both sides21x3x=35+621x -3x =35 +6This simplifies to18x=4118x =41

STEP 4

Finally, to solve for xx, divide both sides of the equation by 1818x=4118x = \frac{41}{18}This is already a simplified fraction, so no further simplification is needed.
So, the solution to the equation is x=4118x = \frac{41}{18}.

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