Question Solve $3(9x-4)-3=5(x+2)$ for $x$ . Round the final answer to 6 decimal places.

Studdy Solution

STEP 1

Assumptions1. The equation is $3(9x-4)-3=5(x+)$ . We are solving for $x$
3. The solution should be written to6 decimal places

STEP 2

First, distribute the $$ in the left-hand side of the equation.
$(9x-4)- =27x -12 -$

STEP 3

implify the left-hand side of the equation.
$27x -12 -3 =27x -15$

STEP 4

Next, distribute the $$ in the right-hand side of the equation.
$(x+2) =x +10$

STEP 5

Now, we have the equation $27x -15 =5x +10$ .

STEP 6

To isolate $x$ , we need to get all terms with $x$ on one side of the equation and constants on the other side. Subtract $5x$ from both sides of the equation.
$27x -5x =15 +10$

STEP 7

implify both sides of the equation.
$22x =25$

STEP 8

Finally, solve for $x$ by dividing both sides of the equation by $22$ .
$x = \frac{25}{22}$

STEP 9

The problem asks for the answer to be rounded to6 decimal places. So, we round $\frac{25}{22}$ to6 decimal places.
$x \approx.136364$ So, the solution to the equation is $x \approx.136364$ .

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