QuestionSolve for $b_{1}$ in the equation $A=\frac{1}{2} h(b_{1}+b_{2})$ . Options: A, B, C, D.

Studdy Solution

STEP 1

Assumptions1. The given formula is $A=\frac{1}{} h\left(b_{1}+b_{}\right)$ . We need to solve this formula for $b_{1}$

STEP 2

First, we need to isolate the term containing $b_{1}$ on one side of the equation. We can do this by multiplying both sides of the equation by2 to remove the fraction.
$2A = h(b_{1}+b_{2})$

STEP 3

Next, we can distribute the $h$ on the right side of the equation.
$2A = hb_{1} + hb_{2}$

STEP 4

Now, we can isolate $b_{1}$ by subtracting $hb_{2}$ from both sides of the equation.
$2A - hb_{2} = hb_{1}$

STEP 5

Finally, we can solve for $b_{1}$ by dividing both sides of the equation by $h$ .
$b_{1} = \frac{2A - hb_{2}}{h}$ Therefore, the solution is option C $b_{1}=\frac{2 A-(h)\left(b_{2}\right)}{h}$ .

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QuestionSolve for $b_{1}$ in the equation $A=\frac{1}{2} h(b_{1}+b_{2})$ . Options: A, B, C, D.

Studdy Solution

STEP 1

Assumptions1. The given formula is $A=\frac{1}{} h\left(b_{1}+b_{}\right)$ . We need to solve this formula for $b_{1}$

STEP 2

First, we need to isolate the term containing $b_{1}$ on one side of the equation. We can do this by multiplying both sides of the equation by2 to remove the fraction.
$2A = h(b_{1}+b_{2})$

STEP 3

Next, we can distribute the $h$ on the right side of the equation.
$2A = hb_{1} + hb_{2}$

STEP 4

Now, we can isolate $b_{1}$ by subtracting $hb_{2}$ from both sides of the equation.
$2A - hb_{2} = hb_{1}$

STEP 5

Finally, we can solve for $b_{1}$ by dividing both sides of the equation by $h$ .
$b_{1} = \frac{2A - hb_{2}}{h}$ Therefore, the solution is option C $b_{1}=\frac{2 A-(h)\left(b_{2}\right)}{h}$ .

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QuestionSolve for b1b_{1}b1​ in the equation A=12h(b1+b2)A=\frac{1}{2} h(b_{1}+b_{2})A=21​h(b1​+b2​). Options: A, B, C, D.

Studdy Solution

STEP 1

Assumptions1. The given formula is A=1h(b1+b)A=\frac{1}{} h\left(b_{1}+b_{}\right)A=1​h(b1​+b​). We need to solve this formula for b1b_{1}b1​

STEP 2

First, we need to isolate the term containing b1b_{1}b1​ on one side of the equation. We can do this by multiplying both sides of the equation by2 to remove the fraction.2A=h(b1+b2)2A = h(b_{1}+b_{2})2A=h(b1​+b2​)

STEP 3

Next, we can distribute the hhh on the right side of the equation.2A=hb1+hb22A = hb_{1} + hb_{2}2A=hb1​+hb2​

STEP 4

Now, we can isolate b1b_{1}b1​ by subtracting hb2hb_{2}hb2​ from both sides of the equation.2A−hb2=hb12A - hb_{2} = hb_{1}2A−hb2​=hb1​

STEP 5

Finally, we can solve for b1b_{1}b1​ by dividing both sides of the equation by hhh.b1=2A−hb2hb_{1} = \frac{2A - hb_{2}}{h}b1​=h2A−hb2​​Therefore, the solution is option C b1=2A−(h)(b2)hb_{1}=\frac{2 A-(h)\left(b_{2}\right)}{h}b1​=h2A−(h)(b2​)​.

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QuestionSolve for $b_{1}$ in the equation $A=\frac{1}{2} h(b_{1}+b_{2})$ . Options: A, B, C, D.

Assumptions1. The given formula is $A=\frac{1}{} h\left(b_{1}+b_{}\right)$ . We need to solve this formula for $b_{1}$

First, we need to isolate the term containing $b_{1}$ on one side of the equation. We can do this by multiplying both sides of the equation by2 to remove the fraction.
$2A = h(b_{1}+b_{2})$

Next, we can distribute the $h$ on the right side of the equation.
$2A = hb_{1} + hb_{2}$

Now, we can isolate $b_{1}$ by subtracting $hb_{2}$ from both sides of the equation.
$2A - hb_{2} = hb_{1}$

Finally, we can solve for $b_{1}$ by dividing both sides of the equation by $h$ .
$b_{1} = \frac{2A - hb_{2}}{h}$ Therefore, the solution is option C $b_{1}=\frac{2 A-(h)\left(b_{2}\right)}{h}$ .