Math  /  Trigonometry

QuestionSolve sin(2x)cos(5x)cos(2x)sin(5x)=0.4\sin (2 x) \cos (5 x)-\cos (2 x) \sin (5 x)=-0.4 for the smallest positive solution. x=x=
Give your answer accurate to two decimal places.

Studdy Solution

STEP 1

1. The equation involves trigonometric identities.
2. We will use the sine difference identity to simplify the equation.
3. We are looking for the smallest positive solution for x x .

STEP 2

1. Apply the sine difference identity.
2. Simplify the equation.
3. Solve for x x .
4. Find the smallest positive solution.

STEP 3

Apply the sine difference identity. The identity states:
sin(a)cos(b)cos(a)sin(b)=sin(ab)\sin(a)\cos(b) - \cos(a)\sin(b) = \sin(a-b)
In this case, let a=2x a = 2x and b=5x b = 5x . Thus, the equation becomes:
sin(2x)cos(5x)cos(2x)sin(5x)=sin((2x)(5x))=sin(3x)\sin(2x)\cos(5x) - \cos(2x)\sin(5x) = \sin((2x) - (5x)) = \sin(-3x)

STEP 4

The equation simplifies to:
sin(3x)=0.4\sin(-3x) = -0.4
Using the property sin(θ)=sin(θ)\sin(-\theta) = -\sin(\theta), we have:
sin(3x)=0.4-\sin(3x) = -0.4
Thus:
sin(3x)=0.4\sin(3x) = 0.4

STEP 5

Solve for 3x 3x using the inverse sine function:
3x=arcsin(0.4)3x = \arcsin(0.4)
Calculate arcsin(0.4)\arcsin(0.4):
3x0.4115 radians3x \approx 0.4115 \text{ radians}

STEP 6

Since the sine function is periodic with period 2π2\pi, the general solution for 3x3x is:
3x=0.4115+2kπor3x=π0.4115+2kπ3x = 0.4115 + 2k\pi \quad \text{or} \quad 3x = \pi - 0.4115 + 2k\pi
where kk is an integer.

STEP 7

Solve for x x by dividing by 3:
For the first solution:
x=0.4115+2kπ3x = \frac{0.4115 + 2k\pi}{3}
For the second solution:
x=π0.4115+2kπ3x = \frac{\pi - 0.4115 + 2k\pi}{3}
Find the smallest positive x x :
For k=0 k = 0 :
x0.411530.1372x \approx \frac{0.4115}{3} \approx 0.1372
For the second solution with k=0 k = 0 :
xπ0.411530.9108x \approx \frac{\pi - 0.4115}{3} \approx 0.9108
The smallest positive solution is:
x0.14x \approx 0.14
The smallest positive solution for x x is:
0.14 \boxed{0.14}

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