QuestionSolve for $y$ : $3x - 4y = \pm 20$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3x -4y = \pm20$ . . We need to solve for $y$ .

STEP 2

First, we need to isolate $y$ in the equation. We can do this by subtracting $x$ from both sides of the equation.
$x -4y -x = \pm20 -x$

STEP 3

implify the equation.
$-y = -3x \pm20$

STEP 4

Now, we need to get rid of the coefficient of $y$ which is $-4$ . We can do this by dividing both sides of the equation by $-4$ .
$\frac{-4y}{-4} = \frac{-3x \pm20}{-4}$

STEP 5

implify the equation.
$y = \frac{3x}{4} \mp5$ So, the solution for $y$ is $y = \frac{3x}{4} \mp5$ .

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QuestionSolve for $y$ : $3x - 4y = \pm 20$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3x -4y = \pm20$ . . We need to solve for $y$ .

STEP 2

First, we need to isolate $y$ in the equation. We can do this by subtracting $x$ from both sides of the equation.
$x -4y -x = \pm20 -x$

STEP 3

implify the equation.
$-y = -3x \pm20$

STEP 4

Now, we need to get rid of the coefficient of $y$ which is $-4$ . We can do this by dividing both sides of the equation by $-4$ .
$\frac{-4y}{-4} = \frac{-3x \pm20}{-4}$

STEP 5

implify the equation.
$y = \frac{3x}{4} \mp5$ So, the solution for $y$ is $y = \frac{3x}{4} \mp5$ .

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QuestionSolve for yyy: 3x−4y=±203x - 4y = \pm 203x−4y=±20.

Studdy Solution

STEP 1

Assumptions1. The equation is 3x−4y=±203x -4y = \pm203x−4y=±20. . We need to solve for yyy.

STEP 2

First, we need to isolate yyy in the equation. We can do this by subtracting xxx from both sides of the equation.x−4y−x=±20−xx -4y -x = \pm20 -xx−4y−x=±20−x

STEP 3

implify the equation.−y=−3x±20-y = -3x \pm20−y=−3x±20

STEP 4

Now, we need to get rid of the coefficient of yyy which is −4-4−4. We can do this by dividing both sides of the equation by −4-4−4.−4y−4=−3x±20−4\frac{-4y}{-4} = \frac{-3x \pm20}{-4}−4−4y​=−4−3x±20​

STEP 5

implify the equation.y=3x4∓5y = \frac{3x}{4} \mp5y=43x​∓5So, the solution for yyy is y=3x4∓5y = \frac{3x}{4} \mp5y=43x​∓5.

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QuestionSolve for $y$ : $3x - 4y = \pm 20$ .

Assumptions1. The equation is $3x -4y = \pm20$ . . We need to solve for $y$ .

First, we need to isolate $y$ in the equation. We can do this by subtracting $x$ from both sides of the equation.
$x -4y -x = \pm20 -x$

implify the equation.
$-y = -3x \pm20$

Now, we need to get rid of the coefficient of $y$ which is $-4$ . We can do this by dividing both sides of the equation by $-4$ .
$\frac{-4y}{-4} = \frac{-3x \pm20}{-4}$

implify the equation.
$y = \frac{3x}{4} \mp5$ So, the solution for $y$ is $y = \frac{3x}{4} \mp5$ .