Math

QuestionSolve for xx in the equation: x=(8.4×103M2s1)(0.36M)3x=(8.4 \times 10^{3} M^{-2} \cdot s^{-1})(0.36 M)^{3}. Include units.

Studdy Solution

STEP 1

Assumptions1. The value of xx is calculated by multiplying 8.4×103Ms18.4 \times10^{3} M^{-} \cdot s^{-1} with (0.36M)3(0.36 M)^{3}. . The units of xx are derived from the units of the given quantities.

STEP 2

First, we need to calculate the value of (0.36M)(0.36 M)^{}. This is done by cubing the value of 0.36M0.36 M.
(0.36M)=0.36M(0.36 M)^{} =0.36^{} M^{}

STEP 3

Now, calculate the value of 0.3630.36^{3}.
0.363=0.0466560.36^{3} =0.046656So, (0.36M)3=0.046656M3(0.36 M)^{3} =0.046656 M^{3}.

STEP 4

Now, we can calculate the value of xx by multiplying 8.4×103M2s18.4 \times10^{3} M^{-2} \cdot s^{-1} with 0.046656M30.046656 M^{3}.
x=(8.4×103M2s1)×(0.046656M3)x = (8.4 \times10^{3} M^{-2} \cdot s^{-1}) \times (0.046656 M^{3})

STEP 5

Calculate the value of xx.
x=(8.4×103M2s1)×0.046656M3=391.9104Ms1x = (8.4 \times10^{3} M^{-2} \cdot s^{-1}) \times0.046656 M^{3} =391.9104 M \cdot s^{-1}

STEP 6

The units of xx are derived from the units of the given quantities. The unit M3M^{3} from (0.36M)3(0.36 M)^{3} cancels out with the M2M^{-2} from 8.4×103M2s18.4 \times10^{3} M^{-2} \cdot s^{-1}, leaving the unit of xx as Ms1M \cdot s^{-1}.
So, x=391.9104Ms1x =391.9104 M \cdot s^{-1}.
The value of xx is 391.9104Ms1391.9104 M \cdot s^{-1}.

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