Math  /  Trigonometry

QuestionSolve for xx. Round to the nearest tenth of a degree, if necessary.

Studdy Solution

STEP 1

1. The triangle IJK \triangle IJK is a right triangle with a right angle at J J .
2. The side IJ IJ is the side adjacent to angle x x .
3. The hypotenuse IK IK is opposite the right angle.
4. We need to find the angle x x using trigonometric ratios.

STEP 2

1. Identify the appropriate trigonometric function.
2. Set up the equation using the trigonometric function.
3. Solve for x x .
4. Round x x to the nearest tenth of a degree.

STEP 3

Identify the appropriate trigonometric function:
Since we have the adjacent side (IJ=23 IJ = 23 ) and the hypotenuse (IK=53 IK = 53 ), we use the cosine function:
cos(x)=AdjacentHypotenuse \cos(x) = \frac{\text{Adjacent}}{\text{Hypotenuse}}

STEP 4

Set up the equation using the cosine function:
cos(x)=2353 \cos(x) = \frac{23}{53}

STEP 5

Solve for x x by taking the inverse cosine:
x=cos1(2353) x = \cos^{-1}\left(\frac{23}{53}\right)

STEP 6

Calculate x x and round to the nearest tenth of a degree:
Using a calculator, find:
xcos1(2353)65.4 x \approx \cos^{-1}\left(\frac{23}{53}\right) \approx 65.4^\circ
The value of x x is:
65.4 \boxed{65.4^\circ}

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