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Question Solve the following linear equations: −6x=18-6 x=18, x−3=12x-3=12, −x4=3-\frac{x}{4}=3.

Studdy Solution

STEP 1

Assumptions
1. We are solving linear equations.
2. Each equation has one variable, xx.
3. We will solve for xx in each equation separately.

STEP 2

Solve the first equation −6x=18-6x = 18.
To isolate xx, we need to divide both sides of the equation by −6-6.
x=18−6x = \frac{18}{-6}

STEP 3

Calculate the value of xx for the first equation.
x=18−6=−3x = \frac{18}{-6} = -3

STEP 4

Solve the second equation x−3=12x - 3 = 12.
To isolate xx, we need to add 33 to both sides of the equation.
x=12+3x = 12 + 3

STEP 5

Calculate the value of xx for the second equation.
x=12+3=15x = 12 + 3 = 15

STEP 6

Solve the third equation −x4=3-\frac{x}{4} = 3.
To isolate xx, we need to multiply both sides of the equation by −4-4.
x=3×(−4)x = 3 \times (-4)

STEP 7

Calculate the value of xx for the third equation.
x=3×(−4)=−12x = 3 \times (-4) = -12
The solutions are: 1) For the first equation −6x=18-6x = 18, x=−3x = -3. 2) For the second equation x−3=12x - 3 = 12, x=15x = 15. 3) For the third equation −x4=3-\frac{x}{4} = 3, x=−12x = -12.

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