Math

Question Solve for yy and graph the solution. Solve the system of linear inequalities: 13y+6<15y6-13y+6<-15y-6 or 2y+383y2y+3\geq8-3y. Plot the endpoints and modify the graph.

Studdy Solution

STEP 1

Assumptions1. We are given two inequalities 13y+6<15y6-13y +6 < -15y -6 and y+383yy +3 \geq8 -3y. . We need to solve for yy in each inequality and graph the solution.
3. We will plot the endpoints and select an endpoint to change it from closed to open.
4. We will select the middle of a segment, ray, or line to delete it.

STEP 2

Let's start by solving the first inequality. We can do this by first adding 15y15y to both sides to get rid of the 15y-15y on the right side.
13y+15y+6<6-13y +15y +6 < -6

STEP 3

implify the left side of the inequality.
2y+6<62y +6 < -6

STEP 4

Subtract 66 from both sides to isolate 2y2y on the left side.
2y<122y < -12

STEP 5

Divide both sides by 22 to solve for yy.
y<y < -

STEP 6

Now, let's solve the second inequality. We can do this by first adding 3y3y to both sides to get rid of the 3y-3y on the right side.
2y+3y+382y +3y +3 \geq8

STEP 7

implify the left side of the inequality.
5y+35y +3 \geq

STEP 8

Subtract 33 from both sides to isolate 5y5y on the left side.
5y55y \geq5

STEP 9

Divide both sides by 55 to solve for yy.
yy \geq

STEP 10

Now, let's graph the solutions. The first inequality, y<6y < -6, is an open interval because it does not include 6-6. So, we draw an open circle at 6-6 and an arrow pointing to the left, indicating all numbers less than 6-6.
The second inequality, yy \geq, is a closed interval because it includes .So,wedrawaclosedcircleat. So, we draw a closed circle at and an arrow pointing to the right, indicating all numbers greater than or equal to $$.
The solution to the given inequalities is the union of these two intervals.

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