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Math

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PROBLEM

Solve for ss.
10r+12s=6s=[]\begin{array}{l} -10 r+12 s=-6 \\ s=[] \end{array}

STEP 1

1. The equation 10r+12s=6 -10r + 12s = -6 is a linear equation in terms of s s .
2. We need to isolate s s on one side of the equation.
3. The equation involves basic algebraic operations such as addition, subtraction, and division.

STEP 2

1. Rearrange the equation to isolate terms involving s s .
2. Solve for s s by performing algebraic operations.
3. Verify the solution by substituting back into the original equation if necessary.

STEP 3

Start with the given equation:
10r+12s=6 -10r + 12s = -6 Our goal is to isolate s s . First, move the term involving r r to the other side of the equation by adding 10r 10r to both sides:
12s=10r6 12s = 10r - 6

STEP 4

Now, solve for s s by dividing every term by 12:
s=10r612 s = \frac{10r - 6}{12} Simplify the expression if possible:
s=10r12612 s = \frac{10r}{12} - \frac{6}{12} s=5r612 s = \frac{5r}{6} - \frac{1}{2}

SOLUTION

Verification is optional in this context, as the solution is expressed in terms of r r .
The solution for s s is:
s=5r612 s = \frac{5r}{6} - \frac{1}{2}

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