Math  /  Algebra

QuestionSolve for cc. 2c+2=62 c+2=6 c=c= \square Submit

Studdy Solution

STEP 1

1. The equation 2c+2=6 2c + 2 = 6 is a linear equation in one variable.
2. The goal is to solve for the variable c c .
3. Basic algebraic operations such as subtraction and division will be used.

STEP 2

1. Isolate the term containing the variable c c .
2. Solve for c c by performing algebraic operations.
3. Verify the solution by substituting it back into the original equation.

STEP 3

Subtract 2 from both sides of the equation to isolate the term with c c :
2c+22=62 2c + 2 - 2 = 6 - 2
Simplifying gives:
2c=4 2c = 4

STEP 4

Divide both sides of the equation by 2 to solve for c c :
2c2=42 \frac{2c}{2} = \frac{4}{2}
Simplifying gives:
c=2 c = 2

STEP 5

Verify the solution by substituting c=2 c = 2 back into the original equation:
Substitute c=2 c = 2 :
2(2)+2=6 2(2) + 2 = 6
Simplify the left-hand side:
4+2=6 4 + 2 = 6
6=6 6 = 6
Both sides are equal, confirming the solution is correct.
The solution is:
c=2 c = \boxed{2}

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