Math  /  Algebra

QuestionSolve. 5r+1015=2r82\frac{5 r+10}{15}=\frac{2 r-8}{2}
The solution is r=\mathrm{r}= \square (Simplify your answer.)

Studdy Solution

STEP 1

1. The equation 5r+1015=2r82\frac{5r+10}{15} = \frac{2r-8}{2} is a rational equation.
2. We need to solve for the variable r r .
3. The equation involves fractions, so we will need to eliminate the fractions to simplify the equation.

STEP 2

1. Eliminate the fractions by finding a common denominator or by cross-multiplying.
2. Simplify the resulting equation.
3. Solve for r r .
4. Check the solution by substituting it back into the original equation.

STEP 3

To eliminate the fractions, we can cross-multiply. This means multiplying the numerator of each fraction by the denominator of the other fraction:
(5r+10)2=(2r8)15 (5r + 10) \cdot 2 = (2r - 8) \cdot 15

STEP 4

Distribute the multiplication on both sides:
Left side: 2(5r+10)=10r+20 2 \cdot (5r + 10) = 10r + 20
Right side: 15(2r8)=30r120 15 \cdot (2r - 8) = 30r - 120

STEP 5

Now, we have the equation: 10r+20=30r120 10r + 20 = 30r - 120

STEP 6

To solve for r r , first move all terms involving r r to one side and constant terms to the other side. Subtract 10r 10r from both sides:
20=30r10r120 20 = 30r - 10r - 120
This simplifies to:
20=20r120 20 = 20r - 120

STEP 7

Add 120 to both sides to isolate terms with r r :
20+120=20r 20 + 120 = 20r
140=20r 140 = 20r

STEP 8

Divide both sides by 20 to solve for r r :
r=14020 r = \frac{140}{20}
Simplify the fraction:
r=7 r = 7

STEP 9

Check the solution by substituting r=7 r = 7 back into the original equation:
Left side: 5(7)+1015=35+1015=4515=3 \frac{5(7) + 10}{15} = \frac{35 + 10}{15} = \frac{45}{15} = 3
Right side: 2(7)82=1482=62=3 \frac{2(7) - 8}{2} = \frac{14 - 8}{2} = \frac{6}{2} = 3
Both sides are equal, confirming that the solution is correct.
The solution is: r=7 \mathrm{r} = \boxed{7}

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