Math Snap

STEP 1

Assumptions1. The given equation is $\frac{5 r+15}{20}=\frac{3 r-36}{3}$

STEP 2

First, we will simplify both sides of the equation by reducing the fractions to their simplest form.On the left side, we can divide both the numerator and the denominator by5. On the right side, we can divide both the numerator and the denominator by.
$$\frac{5 r+15}{20}=\frac{r+}{4}$$$$\frac{ r-36}{}=r-12$$

STEP 3

Now, the simplified equation is$$\frac{r+3}{}=r-12$$

STEP 4

Next, we will eliminate the fraction by multiplying both sides of the equation by4.
$$4 \cdot \frac{r+3}{4}=4 \cdot (r-12)$$

STEP 5

This simplifies to$$r+3=4r-48$$

STEP 6

Now, we will isolate the variable $r$ on one side of the equation. We can do this by subtracting $r$ from both sides of the equation.
$$r+3-r=4r-48-r$$

STEP 7

This simplifies to$$3=3r-48$$

STEP 8

Next, we will isolate $r$ by adding48 to both sides of the equation.
$$3+48=3r-48+48$$

STEP 9

This simplifies to$$51=3r$$

STEP 10

Finally, we will solve for $r$ by dividing both sides of the equation by3.
$$\frac{51}{3}=r$$

This simplifies to$$r=17$$So, the solution to the equation is $r=17$.