Math  /  Algebra

QuestionSolve 10(2y+2)y=2(8y8)10(2 y+2)-y=2(8 y-8).
The solution is y=y=

Studdy Solution

STEP 1

What is this asking? We're asked to solve for the unknown variable yy in a single equation. Watch out! Don't forget to distribute correctly across the parentheses and keep track of your signs!

STEP 2

1. Expand both sides
2. Group like terms
3. Isolate yy
4. Find yy

STEP 3

Let's **expand** the left side of the equation: 10(2y+2)y10(2y + 2) - y.
Distributing the **10** across the parentheses gives us 102y+102y10 \cdot 2y + 10 \cdot 2 - y, which simplifies to 20y+20y20y + 20 - y.

STEP 4

Now, let's **expand** the right side: 2(8y8)2(8y - 8).
Distributing the **2** gives us 28y282 \cdot 8y - 2 \cdot 8, which simplifies to 16y1616y - 16.

STEP 5

So, our equation becomes 20y+20y=16y1620y + 20 - y = 16y - 16.
Much better!

STEP 6

On the left side, we combine the yy terms: 20yy20y - y, which gives us 19y19y.
So, our equation is now 19y+20=16y1619y + 20 = 16y - 16.

STEP 7

Let's move all the yy terms to the left side.
We can do this by adding 16y-16y to both sides: 19y+20+(16y)=16y16+(16y)19y + 20 + (-16y) = 16y - 16 + (-16y).
This simplifies to 3y+20=163y + 20 = -16.

STEP 8

Now, let's move the constant terms to the right side.
We add 20-20 to both sides: 3y+20+(20)=16+(20)3y + 20 + (-20) = -16 + (-20).
This simplifies to 3y=363y = -36.

STEP 9

To **isolate** yy, we divide both sides of the equation 3y=363y = -36 by **3**: 3y3=363 \frac{3y}{3} = \frac{-36}{3} .

STEP 10

This gives us our **final answer**: y=12y = -12.
Awesome!

STEP 11

y=12y = -12

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