Math

QuestionSimplify 5625x83-5 \sqrt[3]{625 x^{8}} fully and express the answer in radical form.

Studdy Solution

STEP 1

Assumptions1. We are given the expression 5625x83-5 \sqrt[3]{625 x^{8}}. . We need to simplify this expression and write the answer in radical form.

STEP 2

First, we can rewrite the expression by separating the number and the variable inside the cube root.
5625x8=5625x8-5 \sqrt[]{625 x^{8}} = -5 \sqrt[]{625} \sqrt[]{x^{8}}

STEP 3

Next, we simplify the cube root of625. The cube root of a number is the value that, when cubed, gives the original number. The cube root of625 is5 because 53=1255^3 =125.
56253x83=55x83-5 \sqrt[3]{625} \sqrt[3]{x^{8}} = -5 \cdot5 \sqrt[3]{x^{8}}

STEP 4

Multiply the two constants outside the cube root.
x83=25x83- \cdot \sqrt[3]{x^{8}} = -25 \sqrt[3]{x^{8}}

STEP 5

Now, we simplify the cube root of x8x^{8}. We know that the cube root of x3x^{3} is xx. Therefore, we can rewrite x8x^{8} as x3x3x2x^{3} \cdot x^{3} \cdot x^{2}.
25x83=25x3x3x23-25 \sqrt[3]{x^{8}} = -25 \sqrt[3]{x^{3} \cdot x^{3} \cdot x^{2}}

STEP 6

We can now simplify the cube root of x3x3x2x^{3} \cdot x^{3} \cdot x^{2}.
25x3x3x23=25xxx23-25 \sqrt[3]{x^{3} \cdot x^{3} \cdot x^{2}} = -25 \cdot x \cdot x \cdot \sqrt[3]{x^{2}}

STEP 7

Multiply the two xx's outside the cube root.
25xxx23=25x2x23-25 \cdot x \cdot x \cdot \sqrt[3]{x^{2}} = -25 x^{2} \sqrt[3]{x^{2}}So, the simplified form of 5625x3-5 \sqrt[3]{625 x^{}} is 25x2x23-25 x^{2} \sqrt[3]{x^{2}}.

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