Math  /  Numbers & Operations

QuestionSimplify. 24\sqrt{24}

Studdy Solution

STEP 1

What is this asking? We need to simplify the square root of 2424.
Basically, we want to find the simplest way to write this radical. Watch out! Don't just grab your calculator!
We want the exact simplified radical form, not a rounded decimal.

STEP 2

1. Find the prime factorization.
2. Simplify the radical.

STEP 3

Let's **break down** 24\sqrt{24} by finding the **prime factorization** of 2424.
This means we want to write 2424 as a product of its prime factors.
Remember, a **prime number** is a whole number greater than 11 that has only two divisors: 11 and itself.

STEP 4

We can start by dividing 2424 by the smallest prime number, 22.
We get 24=21224 = 2 \cdot 12.

STEP 5

1212 isn't prime, so we keep going! 12=2612 = 2 \cdot 6, so now we have 24=22624 = 2 \cdot 2 \cdot 6.

STEP 6

66 is still not prime! 6=236 = 2 \cdot 3.
Finally, we have 24=222324 = 2 \cdot 2 \cdot 2 \cdot 3, and all of these factors are prime!
We can write this more compactly using exponents: 24=23324 = 2^3 \cdot 3.

STEP 7

Now, let's **rewrite** our radical using the prime factorization: 24=233\sqrt{24} = \sqrt{2^3 \cdot 3}.

STEP 8

Remember that the square root of a product is the product of the square roots: ab=ab\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}.
So, we can write 233=233\sqrt{2^3 \cdot 3} = \sqrt{2^3} \cdot \sqrt{3}.

STEP 9

We can **rewrite** 232^3 as 2222^2 \cdot 2, so we have 23=222\sqrt{2^3} = \sqrt{2^2 \cdot 2}.

STEP 10

Using the rule from before, 222=222\sqrt{2^2 \cdot 2} = \sqrt{2^2} \cdot \sqrt{2}.

STEP 11

Since 22=2\sqrt{2^2} = 2, we have 222=22\sqrt{2^2} \cdot \sqrt{2} = 2\sqrt{2}.

STEP 12

Putting it all together, we get 24=233=233=223=223=26\sqrt{24} = \sqrt{2^3 \cdot 3} = \sqrt{2^3} \cdot \sqrt{3} = 2\sqrt{2} \cdot \sqrt{3} = 2\sqrt{2 \cdot 3} = 2\sqrt{6}.

STEP 13

Our simplified radical is 262\sqrt{6}!

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