Math  /  Algebra

QuestionSimplify. 2+10i5+8i\frac{2+10 i}{5+8 i}
Write your answer in the form a + bi. Reduce all fractions. \square

Studdy Solution

STEP 1

What is this asking? We need to simplify a fraction with complex numbers and write the answer in the standard form a+bia + bi, where aa and bb are real numbers. Watch out! Remember that i2=1i^2 = -1.
Don't forget to reduce the fractions at the end!

STEP 2

1. Multiply by the conjugate
2. Simplify and separate

STEP 3

To get rid of the imaginary part in the denominator, we'll **multiply** both the numerator and denominator by the **conjugate** of the denominator.
The conjugate of 5+8i5 + 8i is 58i5 - 8i.
Remember, we change the sign of the imaginary part!

STEP 4

2+10i5+8i58i58i \frac{2 + 10i}{5 + 8i} \cdot \frac{5 - 8i}{5 - 8i} Multiplying by 58i58i\frac{5 - 8i}{5 - 8i} is like multiplying by **one**, so it doesn't change the *value* of our expression, just how it looks!

STEP 5

(2+10i)(58i)=25+2(8i)+10i5+10i(8i)=1016i+50i80i2 (2 + 10i)(5 - 8i) = 2 \cdot 5 + 2 \cdot (-8i) + 10i \cdot 5 + 10i \cdot (-8i) = 10 - 16i + 50i - 80i^2 Since i2=1i^2 = -1, we have 1016i+50i80i2=1016i+50i80(1)=1016i+50i+80=90+34i 10 - 16i + 50i - 80i^2 = 10 - 16i + 50i - 80(-1) = 10 - 16i + 50i + 80 = 90 + 34i

STEP 6

(5+8i)(58i)=55+5(8i)+8i5+8i(8i)=2540i+40i64i2 (5 + 8i)(5 - 8i) = 5 \cdot 5 + 5 \cdot (-8i) + 8i \cdot 5 + 8i \cdot (-8i) = 25 - 40i + 40i - 64i^2 The middle terms add to zero, which is exactly what we want! 2564i2=2564(1)=25+64=89 25 - 64i^2 = 25 - 64(-1) = 25 + 64 = 89

STEP 7

So, our fraction becomes: 90+34i89 \frac{90 + 34i}{89}

STEP 8

We want our answer in the form a+bia + bi, so let's separate the fraction: 90+34i89=9089+3489i \frac{90 + 34i}{89} = \frac{90}{89} + \frac{34}{89}i

STEP 9

Can we simplify the fractions 9089\frac{90}{89} and 3489\frac{34}{89}?
Nope! 89 is a prime number, and neither 90 nor 34 is divisible by 89.
So, we're done!

STEP 10

Our final answer is 9089+3489i\frac{90}{89} + \frac{34}{89}i.

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