Math  /  Algebra

QuestionSelect the correct answer from each drop-down menu.
The given equation has been solved in the table. \begin{tabular}{|c|c|} \hline Step & Statement \\ \hline 1 & 3x10=163 x-10=-16 \\ \hline 2 & 3x10+10=16+103 x-10+10=-16+10 \\ \hline 3 & 3x=63 x=-6 \\ \hline 4 & 3x3=63\frac{3 x}{3}=\frac{-6}{3} \\ \hline 5 & x=2x=-2 \\ \hline \end{tabular}
Use the table to complete each statement.
In step 2, the \square property of equality was applied. In step 4, the \square property of equality was applied.

Studdy Solution

STEP 1

1. The problem involves identifying properties of equality used in solving a linear equation.
2. We need to match each step with the correct property of equality.

STEP 2

1. Identify the property of equality used in Step 2.
2. Identify the property of equality used in Step 4.

STEP 3

In Step 2, the equation goes from 3x10=16 3x - 10 = -16 to 3x10+10=16+10 3x - 10 + 10 = -16 + 10 . This step involves adding the same number (10) to both sides of the equation to maintain equality.
The property of equality applied here is the **Addition Property of Equality**.

STEP 4

In Step 4, the equation goes from 3x=6 3x = -6 to 3x3=63 \frac{3x}{3} = \frac{-6}{3} . This step involves dividing both sides of the equation by the same non-zero number (3) to maintain equality.
The property of equality applied here is the **Division Property of Equality**.
The correct answers are: - In step 2, the **Addition** property of equality was applied. - In step 4, the **Division** property of equality was applied.

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