Math  /  Geometry

QuestionScore: 4/54 / 5 Penalty: 1 off
Question Show Examples 1\angle 1 and 2\angle 2 are vertical angles. If m1=(4x+13)\mathrm{m} \angle 1=(4 x+13)^{\circ} and m2=(7x+4)\mathrm{m} \angle 2=(7 x+4)^{\circ}, then find the value of xx.
Answer Attempt 1 out of 2 \square Submit Answer

Studdy Solution

STEP 1

What is this asking? We need to find the value of x x that makes the measures of two vertical angles equal. Watch out! Don't forget that vertical angles are always equal, so set their expressions equal to each other!

STEP 2

1. Set the expressions equal
2. Solve for x x

STEP 3

Alright, let's start by remembering that vertical angles are equal!
So, we can set the expressions for the angles equal to each other.
We have:
(4x+13)=(7x+4)(4x + 13)^\circ = (7x + 4)^\circ
This equation is our starting point to find x x .

STEP 4

First, let's **subtract 4x 4x from both sides** to get all the x x terms on one side.
This gives us:
13=3x+413 = 3x + 4
Why did we do this?
To isolate the x x terms and make it easier to solve for x x !

STEP 5

Next, **subtract 4 from both sides** to get:
9=3x9 = 3x
Now, we have a simpler equation!
We're getting closer!

STEP 6

Finally, **divide both sides by 3** to solve for x x :
x=3x = 3
And there we have it!
We found the value of x x .

STEP 7

The value of x x that makes the measures of the vertical angles equal is x=3 x = 3 .

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