Math  /  Algebra

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What is the slope of the line that passes through the points (1,6)(-1,6) and (14,3)(14,3) ? Write your answer in simplest form.
Answer Attempt 1 out of 2 \square Submit Answer undefined

Studdy Solution

STEP 1

1. We are given two points on a line: (1,6)(-1, 6) and (14,3)(14, 3).
2. We need to find the slope of the line that passes through these two points.
3. The slope is defined as the change in yy divided by the change in xx.

STEP 2

1. Recall the formula for the slope of a line.
2. Substitute the given points into the formula.
3. Simplify the expression to find the slope in simplest form.

STEP 3

Recall the formula for the slope of a line that passes through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2):
m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}

STEP 4

Substitute the given points (1,6)(-1, 6) and (14,3)(14, 3) into the formula:
Let (x1,y1)=(1,6)(x_1, y_1) = (-1, 6) and (x2,y2)=(14,3)(x_2, y_2) = (14, 3).
m=3614(1) m = \frac{3 - 6}{14 - (-1)}

STEP 5

Simplify the expression to find the slope:
m=3614+1 m = \frac{3 - 6}{14 + 1} m=315 m = \frac{-3}{15}
Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 3:
m=3÷315÷3 m = \frac{-3 \div 3}{15 \div 3} m=15 m = \frac{-1}{5}
The slope of the line is:
15 \boxed{-\frac{1}{5}}

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