Math  /  Algebra

QuestionQuestion Evaluate the function f(x)=3log(x+7)+2f(x)=3 \log (x+7)+2 for x=1x=1. Round the final answer to the nearest two decimal places.

Studdy Solution

STEP 1

1. We are given the function f(x)=3log(x+7)+2 f(x) = 3 \log (x+7) + 2 .
2. We need to evaluate this function for x=1 x = 1 .
3. The final answer should be rounded to the nearest two decimal places.

STEP 2

1. Substitute x=1 x = 1 into the function.
2. Simplify the expression inside the logarithm.
3. Calculate the logarithm.
4. Multiply the logarithm by 3.
5. Add 2 to the result.
6. Round the final answer to two decimal places.

STEP 3

Substitute x=1 x = 1 into the function:
f(1)=3log(1+7)+2 f(1) = 3 \log (1+7) + 2

STEP 4

Simplify the expression inside the logarithm:
f(1)=3log(8)+2 f(1) = 3 \log (8) + 2

STEP 5

Calculate the logarithm (assuming base 10):
log(8)0.9031 \log (8) \approx 0.9031

STEP 6

Multiply the logarithm by 3:
3×0.9031=2.7093 3 \times 0.9031 = 2.7093

STEP 7

Add 2 to the result:
2.7093+2=4.7093 2.7093 + 2 = 4.7093

STEP 8

Round the final answer to two decimal places:
4.71 4.71
The value of f(1) f(1) rounded to two decimal places is:
4.71 \boxed{4.71}

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