Math  /  Algebra

QuestionQuestion 19 (1 point) The height, hh, in centimetres, of a piston moving up and down in an engine cylinder can be modelled by the function h(t)=18sin(50πt)+18h(t)=18 \sin (50 \pi t)+18, where tt is the time, in seconds. What is the piston's minimum height? a) -18 cm b) 18 cm c) 0 cm d) 9 cm

Studdy Solution

STEP 1

1. The function h(t)=18sin(50πt)+18 h(t) = 18 \sin(50 \pi t) + 18 models the height of a piston.
2. The sine function, sin(x)\sin(x), oscillates between -1 and 1.
3. We need to determine the minimum value of h(t) h(t) .

STEP 2

1. Analyze the sine function's range.
2. Determine the minimum value of the function h(t) h(t) .

STEP 3

The sine function, sin(x)\sin(x), has a range of [1,1][-1, 1]. This means that the sine function can take any value between -1 and 1, inclusive.

STEP 4

Substitute the minimum value of sin(x)\sin(x) into the function h(t)=18sin(50πt)+18 h(t) = 18 \sin(50 \pi t) + 18 .
The minimum value of sin(x)\sin(x) is -1. Therefore, substitute 1-1 into the function:
h(t)=18(1)+18 h(t) = 18(-1) + 18 h(t)=18+18 h(t) = -18 + 18 h(t)=0 h(t) = 0
Thus, the piston's minimum height is 0 \boxed{0} cm.
The correct answer is c)0cm \boxed{c) \, 0 \, \text{cm}} .

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